XSLT를 사용하여 요소 정렬

Question

특정 요소를 정렬하기위한 요구 사항이 있습니다. 그러나 나는 어떻게 그렇게 할 것인지 모른다. 내가 본 XSLT를 시도했지만 원하는 출력을 얻을 수 없습니다. 입력 XML은 다음과 같이이다 :

<SyncCredit xmlns="http://schema.XYZ.com/XYZOAGIS/2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" releaseID="9.2" versionID="2.12.3"> 
    <Data> 
    <AccountingNo>ERP_12344</AccountingNo> 
    <Credit> 
     <Header> 
     <Name>Supplier Bank</Name> 
     <Date>02-08-2017</Date> 
     </Header> 
     <Payment> 
     <ID>111</ID> 
     <Date>02-01-2017</Date> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="PassportNo">1000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="TaxIdentificationNo">5000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     </Payment> 
     <Payment> 
     <ID>222</ID> 
     <Date>02-05-2017</Date> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="BankPartyNo">4000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="DriverLicense">2000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     </Payment> 
    </Credit> 
    </Data> 
</SyncCredit> 

내 예상 출력은, 다음과 같이

<SyncCredit xmlns="http://schema.XYZ.com/XYZOAGIS/2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" releaseID="9.2" versionID="2.12.3"> 
    <Data> 
    <AccountingNo>ERP_12344</AccountingNo> 
    <Credit> 
     <Header> 
     <Name>Supplier Bank</Name> 
     <Date>02-08-2017</Date> 
     </Header> 
     <Payment> 
     <ID>111</ID> 
     <Date>02-01-2017</Date> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="PassportNo">1000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     </Payment> 
     <Payment> 
     <ID>222</ID> 
     <Date>02-05-2017</Date> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="DriverLicense">2000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     </Payment> 
     <Payment> 
     <ID>222</ID> 
     <Date>02-05-2017</Date> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="BankPartyNo">4000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     </Payment> 
     <Payment> 
     <ID>111</ID> 
     <Date>02-01-2017</Date> 
     <Transaction> 
      <BookNo>AA-111</BookNo> 
      <Creditor> 
      <PartyID> 
       <ID schemeName="TaxIdentificationNo">5000</ID> 
      </PartyID> 
      </Creditor> 
     </Transaction> 
     </Payment> 
    </Credit> 
    </Data> 
</SyncCredit> 

채권자/PartyID/ID 요소가 그대로 다른 요소를 유지하면서 정렬한다. 그러나 정렬 된 채권자/PartyID/ID를 각 <Payment> 노드로 분할해야합니다. XSLT v2.0을 사용하고 있습니다. 내가 제대로 내가 가진 참조, 내가 얻을 출력에서 ​​<xsl:perform-sort> 사용/PartyID이/ID를 채권 금융을 정렬 할 수 있어요,하지만 이런 식이다 : 이것은 내 XSLT이다

<Payment> 
    <Transaction xmlns="http://schema.XYZ.com/XYZOAGIS/2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
    <BookNo>AA-111</BookNo> 
    <Creditor> 
     <PartyID> 
     <ID schemeName="PassportNo">1000</ID> 
     </PartyID> 
    </Creditor> 
    </Transaction> 
    <Transaction xmlns="http://schema.XYZ.com/XYZOAGIS/2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
    <BookNo>AA-111</BookNo> 
    <Creditor> 
     <PartyID> 
     <ID schemeName="DriverLicense">2000</ID> 
     </PartyID> 
    </Creditor> 
    </Transaction> 
    <Transaction xmlns="http://schema.XYZ.com/XYZOAGIS/2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
    <BookNo>AA-111</BookNo> 
    <Creditor> 
     <PartyID> 
     <ID schemeName="BankPartyNo">4000</ID> 
     </PartyID> 
    </Creditor> 
    </Transaction> 
    <Transaction xmlns="http://schema.XYZ.com/XYZOAGIS/2" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
    <BookNo>AA-111</BookNo> 
    <Creditor> 
     <PartyID> 
     <ID schemeName="TaxIdentificationNo">5000</ID> 
     </PartyID> 
    </Creditor> 
    </Transaction> 

, 그것은 완료되지 않은 I 때문에 Header 및 Payment.i에서 요소를 복사하는 방법을 알지 못합니다. 트랜잭션 요소에서 XSLT 만 시도했습니다.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xpath-default-namespace="http://schema.XYZ.com/XYZOAGIS/2"> 
<xsl:output method="xml" omit-xml-declaration="yes" indent="no"/> 
<xsl:template match="/"> 
    <xsl:variable name="Transaction"> 
     <xsl:perform-sort select="SyncCredit/Data/Credit/Payment/Transaction"> 
      <xsl:sort data-type="number" select="Creditor/PartyID/ID"/> 
     </xsl:perform-sort> 
    </xsl:variable> 
    <Payment> 
     <xsl:copy-of select="$Transaction"/> 
    </Payment> 
</xsl:template> 

은 사전에 감사합니다. 나는이 상황을 제대로 이해한다면

Answer 1

, 당신은하고 싶지 :

XSLT

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
xpath-default-namespace="http://schema.XYZ.com/XYZOAGIS/2" 
xmlns="http://schema.XYZ.com/XYZOAGIS/2"> 
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<!-- identity transform --> 
<xsl:template match="@*|node()"> 
    <xsl:copy> 
     <xsl:apply-templates select="@*|node()"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="Credit"> 
    <xsl:copy> 
     <xsl:copy-of select="Header"/> 
     <xsl:apply-templates select="Payment/Transaction"> 
      <xsl:sort select="Creditor/PartyID/ID" data-type="number" order="ascending"/> 
     </xsl:apply-templates> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="Transaction"> 
    <Payment> 
     <xsl:copy-of select="../ID, ../Date, ."/> 
    </Payment> 
</xsl:template> 

</xsl:stylesheet>