C++ 다시 그려진 벡터에 데이터를 반환하는 함수

Question

텍스트 파일을 읽고 인수로 참조되는 벡터를 채우는 함수가 있습니다.

vect.push_back(TempArray); 

은 내 실수로 인한 행입니다. 이견있는 사람?

Error 1 error C2664: 'void std::vector<_Ty>::push_back(double *&&)' : cannot convert parameter 1 from 'std::vector<_Ty>' to 'double *&&' d:\aul_c++_12102014\aul_c++_rk_version_12182014\aul\aul\projection.h 206 1 AUL 

int projection::import_inputTables(string input_file, string output_file, int dimen, vector<double*> &vect, long col_filler, long row_filler, string delim, int OptArgVar)     
{     

long i=0,j=0,k=0;    

int total_Col = dimen; 
long MaxLinesNum = 100000; 
const string DELIM = delim; 
string Line; 
string LineCell; 
long LineCounter = 0; 
long LinesRead = 0; 
int LineReadPoint = 0; 

//Determines number of lines to be read 
    if (OptArgVar == 0) //Read untill the end 
    { 
     MaxLinesNum = 100000; 
    } 
    else if (OptArgVar == 1) 
    { 
     MaxLinesNum = 1; 
    } 
    else if (OptArgVar == 2) 
    { 
     MaxLinesNum = 51; 
    } 

ifstream input_stream; 
input_stream.open(input_file); 

if (input_stream.is_open()) 
{ 
    while(MaxLinesNum > LinesRead) 
    { 
     getline(input_stream,Line); 
     if (LineCounter >= col_filler) 
     { 
      vector<double> TempArray; 

      for (j = 0; (j < total_Col); j++) //Column Loop 
      { 
       LineCell = Line.substr(0,Line.find(DELIM)); 
       Line.erase(0,Line.find(DELIM) + DELIM.length()); 

       TempArray.push_back(stod(LineCell)); 

      } 

      vect.push_back(TempArray); 
      vector<double>().swap(TempArray);   

      LinesRead++; 
      LineCounter++; 
     } 
     else 
     { 
      LineCounter++; 
     } 

     if (MaxLinesNum == LinesRead) //Read only the needed number of lines --- Will read entire file if OptArgVar is set to 0 
      break; 
    } 
} 
else 
{ 
    cout << "Could Not Open File" << endl; 
} 

//PRINT STATEMENT DO NOT DELETE 
input_stream.close(); 

return vect.size(); 

/*ofstream out(output_file);  
out.precision(10); 
for (j = 0; j < vect.size(); j++){    
    for (i = 0; i <= total_Col; i++){   
     out << vect.at(j)[i]<< '\t';   
    }   
    out << '\n';  
}    
out.close();*/ 



}    

Answer 1

는

vector<vector<double>> &vect