.xsd 스키마를 만들고 특성을 지정해야합니다. 내가 어떻게 할 수 있니?XSD 특성 지정
<?xml version="1.0" encoding="UTF-8"?>
<ConfigData>
<GlobalSettings>
<Logging param="Off"/> <-- param can be only in 'On' or 'Off' statement -->
</GlobalSettings>
</ConfigData>
나는 이런 식으로 뭔가를 만들어,하지만
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="ConfigData">
<xs:complexType>
<xs:element name="GlobalSettings">
<xs:complexType>
<xs:simpleType name="statement">
<xs:restriction base="xs:string">
<xs:enumeration value="On"/>
<xs:enumeration value="Off"/>
</xs:restriction>
</xs:simpleType>
<xs:element name="Logging">
<xs:complexType>
<xs:extension base="xs:string">
<xs:attribute name="param" type="statement" use="required"/>
</xs:extension>
</xs:complexType>
</xs:element>
</xs:complexType>
</xs:element>
</xs:complexType>
</xs:element>
</xs:schema>
유익한 질문이 있으시면 pls – Naren
질문에 대한 대답이 도움이 되었습니까? –