Android MySQL 사용자가 관리자인지 확인하십시오.

Question

사용자 이름과 비밀번호를 입력하는 로그인 양식이 있습니다.

은 무엇 내가 달성하고자하는 것은 :

• 확인 사용자가 관리자, 관리자, 일반 사용자의 경우.

• 그런 다음 나는 건배/사용자가 관리자/관리자/일반 사용자임을 에코 표시됩니다

이는 로그인 양식에 대한 내 전류 소스 코드입니다.

import android.content.Context; 
import android.content.Intent; 
import android.content.SharedPreferences; 
import android.os.Bundle; 
import android.support.v4.app.Fragment; 
import android.util.Log; 
import android.view.LayoutInflater; 
import android.view.View; 
import android.view.ViewGroup; 
import android.widget.Button; 
import android.widget.EditText; 
import android.widget.Toast; 

import com.android.volley.AuthFailureError; 
import com.android.volley.Request; 
import com.android.volley.RequestQueue; 
import com.android.volley.Response; 
import com.android.volley.VolleyError; 
import com.android.volley.toolbox.StringRequest; 
import com.android.volley.toolbox.Volley; 

import java.util.HashMap; 
import java.util.Map; 


public class TwoFragment extends Fragment{ 
View view; 
    Button reg; 



    //Defining views 
    private EditText editTextEmail; 
    private EditText editTextPassword; 
    private Button buttonLogin; 


    //boolean variable to check user is logged in or not 
    //initially it is false 
    private boolean loggedIn = false; 
    public TwoFragment() { 
     // Required empty public constructor 
    } 

    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
    } 

    @Override 
    public View onCreateView(LayoutInflater inflater, ViewGroup container, 
          Bundle savedInstanceState) { 
     // Inflate the layout for this fragment 
     view = inflater.inflate(R.layout.fragment_two, container, false); 
     reg = (Button) view.findViewById(R.id.button); 
     buttonLogin = (Button) view.findViewById(R.id.btnsignin); 
     buttonLogin.setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View view) { 
       login(); 
      } 
     }); 

     editTextEmail = (EditText) view.findViewById(R.id.txtemail); 
     editTextPassword = (EditText) view.findViewById(R.id.editText); 
     reg.setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View view) { 
       Intent i = new Intent(getActivity(), managerreg.class); 
       startActivity(i); 
      } 
     }); 



     return view; 
    } 

    @Override 
    public void onResume() { 
     super.onResume(); 
     //In onresume fetching value from sharedpreference 
     SharedPreferences sharedPreferences = getContext().getSharedPreferences(Config.SHARED_PREF_NAME, Context.MODE_PRIVATE); 

     //Fetching the boolean value form sharedpreferences 
     loggedIn = sharedPreferences.getBoolean(Config.LOGGEDIN_SHARED_PREF, false); 

     //If we will get true 
     if(loggedIn){ 
      //We will start the Profile Activity 
      Intent intent = new Intent(getActivity(), MainActivity.class); 
      startActivity(intent); 
     } 
    } 

    private void login(){ 
     //Getting values from edit texts 
     final String username = editTextEmail.getText().toString().trim(); 
     final String password = editTextPassword.getText().toString().trim(); 



     //Creating a string request 
     StringRequest stringRequest = new StringRequest(Request.Method.POST, Config.LOGIN_URL, 
       new Response.Listener<String>() { 
        @Override 
        public void onResponse(String response) { 
         //If we are getting success from server 
         if(response.equalsIgnoreCase(Config.LOGIN_SUCCESS)){ 
          //Creating a shared preference 
          SharedPreferences sharedPreferences = getActivity().getSharedPreferences(Config.SHARED_PREF_NAME, Context.MODE_PRIVATE); 

          //Creating editor to store values to shared preferences 
          SharedPreferences.Editor editor = sharedPreferences.edit(); 

          //Adding values to editor 
          editor.putBoolean(Config.LOGGEDIN_SHARED_PREF, true); 
          editor.putString(Config.USERNAME_SHARED_PREF,username); 


          //Saving values to editor 
          editor.commit(); 

          //Starting profile activity 
          Intent intent = new Intent(getActivity(), MainActivity.class); 
          startActivity(intent); 
         }else{ 
          //If the server response is not success 
          //Displaying an error message on toast 
          Toast.makeText(getActivity(), "Invalid username or password", Toast.LENGTH_LONG).show(); 
         } 
        } 
       }, 
       new Response.ErrorListener() { 
        @Override 
        public void onErrorResponse(VolleyError error) { 
         //You can handle error here if you want 
        } 
       }){ 
      @Override 
      protected Map<String, String> getParams() throws AuthFailureError { 
       Map<String,String> params = new HashMap<>(); 
       //Adding parameters to request 
       params.put(Config.KEY_USERNAME, username); 
       params.put(Config.KEY_PASSWORD, password); 


       //returning parameter 
       return params; 
      } 
     }; 

     //Adding the string request to the queue 
     RequestQueue requestQueue = Volley.newRequestQueue(getActivity().getApplicationContext()); 
     requestQueue.add(stringRequest); 
    } 



} 

이 현재 PHP이다 : 나는 사용자가 관리자인지 아닌지 확인하는 방법을 모르는

<?php 

    if($_SERVER['REQUEST_METHOD']=='POST'){ 
     $username = $_POST['username']; 
     $password = $_POST['password']; 




     require_once('dbConnect.php'); 

    $sql = "SELECT * FROM managerreg WHERE username = '$username' AND password = BINARY '".md5($_POST['password'])." "; 

     $result = mysqli_query($con,$sql); 

     $check = mysqli_fetch_array($result); 

     if(isset($check)){ 
      echo 'success'; 
     }else{ 
      echo 'failure'; 
     } 
    } 

.

Answer 1

서비스에 사용자 이름과 암호를 전달할 때 응답에 사용자 ID 등의 데이터도 포함되어야 프로그램에서이를 비교 한 다음 누가 응용 프로그램에 로그인했는지 알 수 있습니다.