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나는 scikit에서 혼란 행렬을 사용하고 있습니다. 하지만 음모에서는 소수점 1 자리 만 필요합니다 (그림 A). 배열로 (그림 B) 어떤 코드로 변경할 수 있습니까? !!!!!!!!!!!!!!!어떻게 파이썬에서 혼돈 행렬 플롯을 십진수로 1 개만 만들 수 있습니까?
그림 A
그림 B
import itertools
import numpy as np
import matplotlib.pyplot as plt
from sklearn import svm, datasets
from sklearn.model_selection import train_test_split
from sklearn.metrics import confusion_matrix
# import some data to play with
iris = datasets.load_iris()
X = iris.data
y = iris.target
class_names = iris.target_names
# Split the data into a training set and a test set
X_train, X_test, y_train, y_test = train_test_split(X, y, random_state=0)
# Run classifier, using a model that is too regularized (C too low) to see
# the impact on the results
classifier = svm.SVC(kernel='linear', C=0.01)
y_pred = classifier.fit(X_train, y_train).predict(X_test)
def plot_confusion_matrix(cm, title='Confusion matrix', cmap=plt.cm.Oranges):
plt.imshow(cm, interpolation='nearest', cmap=cmap)
plt.title(title)
plt.colorbar()
tick_marks = np.arange(len(iris.target_names))
plt.xticks(tick_marks, rotation=45)
ax = plt.gca()
ax.set_xticklabels((ax.get_xticks() +1).astype(str))
plt.yticks(tick_marks)
thresh = cm.max()/2.
for i, j in itertools.product(range(cm.shape[0]), range(cm.shape[1])):
plt.text(j, i, cm[i, j],
horizontalalignment="center",
color="white" if cm[i, j] > thresh else "black")
plt.tight_layout()
plt.ylabel('True label')
plt.xlabel('Predicted label')
cm = confusion_matrix(y_test, y_pred)
np.set_printoptions(precision=1) #!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
print('Confusion matrix, without normalization')
print(cm)
fig, ax = plt.subplots()
plot_confusion_matrix(cm)
plt.show()