2017-02-28 16 views
-1

내 목표 중 1 단계가 실현되었습니다 (감사합니다 @akrun). 그러나 나는 골라인을 넘을 수 없습니다! 매우 빨리 응답 한 첫 번째 질문을 수행하면서도 여전히 막대 그래프를 만들 수 없습니다. LimeSurvey API 응답을 사용하여 생성 된 데이터 프레임의 동적 R 막대 그래프

내가 내 동적 출력 모양을하고 싶은의 작업 예입니다

library(dplyr) 
library(ggplot2) 
library(tidyr) 
df <- data.frame(timeline = Sys.Date() - 1:10, 
       q3 = sample(c("Yes", "No"), size = 10, replace = T), 
       q4 = sample(c("Yes", "No"), size = 10, replace = T), 
       q5 = sample(c("Yes", "No"), size = 10, replace = T), 
       q6 = sample(c("Yes", "No"), size = 10, replace = T), 
       q7 = sample(c("Yes", "No"), size = 10, replace = T), 
       q8 = sample(c("Yes", "No"), size = 10, replace = T), 

       stringsAsFactors = F) %>% 
    mutate(q3 = ifelse(q3 == "Yes", 1, 0), 
      q4 = ifelse(q4 == "Yes", 1, 0), 
      q5 = ifelse(q5 == "Yes", 1, 0), 
      q6 = ifelse(q6 == "Yes", 1, 0), 
      q7 = ifelse(q7 == "Yes", 1, 0), 
      q8 = ifelse(q8 == "Yes", 1, 0) 

    ) %>% 
    gather(key = question, value = value, q3, q4, q5, q6, q7, q8) 

g <- ggplot(df, aes(x = timeline, y = value, fill = question)) + 
    geom_bar(stat = "identity") 

g 

내가이 만든 가져옵니다 dataframe의 예입니다 help 이후에 도착 곳이다. 열의 수, 이름 또는 관측 수를 알지 못하므로 동적으로 작동해야합니다.

Appetite <- c("No","Yes","No","No","No","No","No","No","No") 
Dental.Health <- c("No","Yes","No","No","No","No","Yes","Yes","No") 
Dry.mouth <- c("No","Yes","Yes","Yes","Yes","No","Yes","Yes","No") 
Mouth.opening <- c("No","No","Yes","Yes","Yes","No","Yes","Yes","No") 
Pain.elsewhere <- c("No","Yes","No","No","No","No","No","No","No") 
Sleeping <- c("No","No","No","No","No","Yes","No","No","No") 
Sore.mouth <- c("No","No","Yes","Yes","No","No","No","No","No") 
Swallowing <- c("No","No","No","No","Yes","No","No","No","No") 
Cancer.treatment <- c("No","No","Yes","Yes","No","Yes","No","No","No") 
Support.for.my.family <- c("No","No","Yes","Yes","No","No","No","No","No") 
Fear.of.cancer.coming.back <- c("No","No","Yes","Yes","No","No","Yes","No","No") 
Intimacy <- c("Yes","No","No","No","No","No","No","No","No") 
Dentist <- c("No","Yes","No","No","No","No","No","No","No") 
Dietician <- c("No","No","Yes","Yes","No","No","No","No","No") 
Date.submitted <- c("2002-07-25 00:00:00", 
       "2002-09-05 00:00:00", 
       "2003-01-09 00:00:00", 
       "2003-01-09 00:00:00", 
       "2003-07-17 00:00:00", 
       "2003-11-06 00:00:00", 
       "2004-12-17 00:00:00", 
       "2005-06-03 00:00:00", 
       "2005-12-17 00:00:00") 

theDates <- as.Date(Date.submitted, "%Y-%m-%d %T") 

theDataFrame <- data.frame(timeline = as.list(theDates), 
          Appetite, 
          Dental.Health, 
          Dry.mouth, 
          Mouth.opening, 
          Pain.elsewhere, 
          Sleeping, 
          Sore.mouth, 
          Swallowing, 
          Cancer.treatment, 
          Support.for.my.family, 
          Fear.of.cancer.coming.back, 
          Intimacy, 
          Dentist, 
          Dietician, 
          stringsAsFactors = F) %>% 
    theDataFrame[-1] <- lapply(theDataFrame[-1], function(x) as.integer(x=="Yes")) %>% 
    gather(key = question, value = value, as.list(theDataFrame)) 

go <- ggplot(theDataFrame, aes(x = timeline, y = value, fill = question)) + 
    geom_bar(stat = "identity") 

go 

나는 어떻게 모으는가에 대한 오해가있을 것입니다. 그러나 저는 그 주위에 머리를 들이지 않는 것 같습니다.

+0

이 무엇을 달성하고자합니까? 당신의 실례는 나를 위해 일한다. 무엇을 바꾸고 싶습니까? – ottlngr

+0

두 번째 작업을해야합니다. 내가 만든 데이터 프레임은 LimeSurvey에 대한 API 호출에서 반환되는 데이터의 예입니다. 변수와 관측치의 수가 다를 것이기 때문에 동적으로 작업해야합니다 (모든 열의 수/이름을 알지 못함) –

답변

0

In his comment, OP는 두 번째 예제가 작동하도록 요청했습니다. 이는 영업 이익의 코드에 약간의 수정을 수행 할 수 있습니다

library(tidyr) 
library(ggplot2) 

Appetite <- c("No","Yes","No","No","No","No","No","No","No") 
Dental.Health <- c("No","Yes","No","No","No","No","Yes","Yes","No") 
Dry.mouth <- c("No","Yes","Yes","Yes","Yes","No","Yes","Yes","No") 
Mouth.opening <- c("No","No","Yes","Yes","Yes","No","Yes","Yes","No") 
Pain.elsewhere <- c("No","Yes","No","No","No","No","No","No","No") 
Sleeping <- c("No","No","No","No","No","Yes","No","No","No") 
Sore.mouth <- c("No","No","Yes","Yes","No","No","No","No","No") 
Swallowing <- c("No","No","No","No","Yes","No","No","No","No") 
Cancer.treatment <- c("No","No","Yes","Yes","No","Yes","No","No","No") 
Support.for.my.family <- c("No","No","Yes","Yes","No","No","No","No","No") 
Fear.of.cancer.coming.back <- c("No","No","Yes","Yes","No","No","Yes","No","No") 
Intimacy <- c("Yes","No","No","No","No","No","No","No","No") 
Dentist <- c("No","Yes","No","No","No","No","No","No","No") 
Dietician <- c("No","No","Yes","Yes","No","No","No","No","No") 
Date.submitted <- 
    c("2002-07-25 00:00:00", "2002-09-05 00:00:00", "2003-01-09 00:00:00", 
    "2003-01-09 00:00:00", "2003-07-17 00:00:00", "2003-11-06 00:00:00", 
    "2004-12-17 00:00:00", "2005-06-03 00:00:00", "2005-12-17 00:00:00") 

theDataFrame <- data.frame(
    timeline = as.Date(Date.submitted), 
    Appetite, Dental.Health, Dry.mouth, Mouth.opening, Pain.elsewhere, 
    Sleeping, Sore.mouth, Swallowing, Cancer.treatment, Support.for.my.family, 
    Fear.of.cancer.coming.back, Intimacy, Dentist, Dietician, 
    stringsAsFactors = FALSE) 

theDataFrame[-1] <- lapply(theDataFrame[-1], function(x) as.integer(x=="Yes")) 
theDataFrame <- theDataFrame %>% gather(question, value, -timeline) 

go <- ggplot(theDataFrame, aes(x = timeline, y = value, fill = question)) + 
    geom_col() 
go 

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