mysql 5.5.44에 대한 트리거를 만드는 방법은 무엇입니까?

Question

s = "CREATE TABLE " + tableName +"\n" + 
    "(\n" + 
    " " + tablelower + "_currentid INT PRIMARY KEY AUTO_INCREMENT,\n" + 
    " " + tablelower + "_id VARCHAR(8) NOT NULL,\n" + 
    " " + tablelower + "_name VARCHAR(45) NOT NULL,\n" + 
    " " + tablelower + "_type VARCHAR(45) NOT NULL,\n" + 
    " " + tablelower + "_topic VARCHAR(255) NOT NULL,\n" + 
    " " + tablelower + "_pin VARCHAR(6) NOT NULL,\n" + 
    " " + tablelower + "_device VARCHAR(100) NOT NULL,\n" + 
    " " + tablelower + "_device_id INT NOT NULL,\n" + 
    " FOREIGN KEY(" + tablelower + "_device_id) REFERENCES Devices(device_currentid)\n" + 
    ");\n" + 
    "\n" + 
    " delimiter | \n" + 
    " CREATE TRIGGER " + tablelower + "_trigger BEFORE INSERT ON " + tableName + 
    " FOR EACH ROW\n" + 
    " BEGIN\n" + 
    " SET new." + tablelower + "_id = CONCAT('" + topic + "',LPAD((SELECT AUTO_INCREMENT FROM information_schema.TABLES WHERE TABLE_SCHEMA = DATABASE() AND TABLE_NAME = '" + tableName + "'),4,'0'));\n" + 
    " SET new." + tablelower + "_topic = CONCAT((SELECT device_topic FROM Devices WHERE device_name LIKE new." + tablelower + "_device),'/',(new." + tablelower + "_id));\n" + 
    " END;\n" + 
    " | \n" + 
    " delimiter ;"; 

    mysqlconn.createStatement().execute(s); 

위의 코드는 문자열 변수 인 tableName과 tablelower에 주어진 이름으로 테이블과 트리거를 만드는 코드입니다. 이것은 내가 쓴 첫 번째 버전이며, 나는 아래의 오류가 발생되었습니다 여기에 나는이 스레드 Error while creating trigger through JDBC on mysql5.5과 문서 http://dev.mysql.com/doc/refman/5.5/en/trigger-syntax.html를 발견하고 나는 모두 StringBuilder에 내 코드를 변경했습니다

You have an error in your SQL syntax; check the manual that corresponds 
to your MySQL server version for the right syntax to use near 'delimiter | 
CREATE TRIGGER tablename_trigger BEFORE INSERT ON tablename FO' at line 14 

Google 도움말 후 :

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DELIMITER // CREATE TRIGGER reedswitchid_trigger BEFORE INSERT ON ReedSwitches' at line 1.

내가 자바를 통해이를 실행하고 있고 MySQL 서버가 Raspbe에 :

  tableCreation.append("CREATE TABLE " + tableName); 
      tableCreation.append("("); 
      tableCreation.append(tablelower + "_currentid INT PRIMARY KEY AUTO_INCREMENT,"); 
      tableCreation.append(tablelower + "_id VARCHAR(10) NOT NULL,"); 
      tableCreation.append(tablelower + "_name VARCHAR(45) NOT NULL,"); 
      tableCreation.append(tablelower + "_type VARCHAR(45) NOT NULL,"); 
      tableCreation.append(tablelower + "_topic VARCHAR(255) NOT NULL,"); 
      tableCreation.append(tablelower + "_pin VARCHAR(6) NOT NULL,"); 
      tableCreation.append(tablelower + "_device VARCHAR(100) NOT NULL,"); 
      tableCreation.append(tablelower + "_device_id INT NOT NULL,"); 
      tableCreation.append("FOREIGN KEY(" + tablelower + "_device_id) REFERENCES Devices(device_currentid)"); 
      tableCreation.append("); "); 

      tableCreation.append("DELIMITER // "); 
      tableCreation.append(" CREATE"); 
      tableCreation.append(" TRIGGER " + tablelower + "id_trigger "); 
      tableCreation.append(" BEFORE INSERT"); 
      tableCreation.append(" ON " + tableName + " FOR EACH ROW"); 
      tableCreation.append(" BEGIN"); 
      tableCreation.append(" SET new." + tablelower + "_id = CONCAT('" + topic + "',LPAD((SELECT AUTO_INCREMENT FROM information_schema.TABLES WHERE TABLE_SCHEMA = DATABASE() AND TABLE_NAME = '" + tableName + "'),4,'0'));"); 
      tableCreation.append(" SET new." + tablelower + "_topic = CONCAT((SELECT device_topic FROM Devices WHERE device_name LIKE new." + tablelower + "_device),'/',(new." + tablelower + "_id));"); 
      tableCreation.append(" END;//"); 
      tableCreation.append("DELIMITER ; "); 

      mysqlconn.createStatement().execute(tableCreation.toString()); 

는하지만 여전히 이러한 변경 후 나는이 오류 rry pi 2. 더 많은 정보 댓글과 에 대해 나는 SQL 초보자입니다. 감사

편집 : JDBC Stateent # executeXXX 방법이 단일 SQL 문, 한 번에없는 여러 개의 문을 실행하기위한 것입니다

You have an error in your SQL syntax; check the manual that corresponds to >your MySQL server version for the right syntax to use near 'SET >new.lightsensor_topic = CONCAT((SELECT device_topic FROM Devices WHERE >devic' at line 1. Exiting

   tabl = "CREATE TABLE " + tableName + 
       "(" + " " + tablelower + "_currentid INT PRIMARY KEY AUTO_INCREMENT, " + 
       tablelower + "_id VARCHAR(8) NOT NULL, " + 
       tablelower + "_name VARCHAR(45) NOT NULL, " + 
       tablelower + "_type VARCHAR(45) NOT NULL, " + 
       tablelower + "_topic VARCHAR(255) NOT NULL, " + 
       tablelower + "_pin VARCHAR(6) NOT NULL, " + 
       tablelower + "_device VARCHAR(100) NOT NULL, " + 
       tablelower + "_device_id INT NOT NULL, " + 
       "FOREIGN KEY(" + tablelower + "_device_id) REFERENCES Devices(device_currentid)" + 
       ")"; 
      trigg= 
       " CREATE TRIGGER " + tablelower + "_trigger BEFORE INSERT ON " + tableName + 
       " FOR EACH ROW" + 
       " SET new." + tablelower + "_id = CONCAT('" + topic + "',LPAD((SELECT AUTO_INCREMENT FROM information_schema.TABLES WHERE TABLE_SCHEMA = DATABASE() AND TABLE_NAME = '" + tableName + "'),4,'0'))" + 
       " SET new." + tablelower + "_topic = CONCAT((SELECT device_topic FROM Devices WHERE device_name LIKE new." + tablelower + "_device),'/',(new." + tablelower + "_id))" + 
       " END"; 

     mysqlconn = data.getConnection(); 
     mysqlconn.createStatement().execute(tabl); 
     mysqlconn.createStatement().execute(trigg); 

Answer 1

.
일부 데이터베이스/드라이버 구현이 이것을 허용하더라도 비표준 방식이며 이식 가능하지 않으므로 간단히 사용하지 마십시오. JDBC에

이 DELIMITER x 명령을 사용하지 않는 명령 SQL의 끝에 세미콜론 ;를 사용하지 않는

• :

  String s1 = "CREATE TABLE (.......)"; 
  String s2 = "CREATE TRIGGER .......END"; 
  mysqlconn.createStatement().execute(s1); 
  mysqlconn.createStatement().execute(s2); 
  

  두 가지 중요한 사항 :
  
  두 개의 문으로 코드를 분할 - 그것은 SQL 명령이 아니지만 mysql - 클라이언트 명령, 데이터베이스가 그것을 recogize하지 않습니다