이 메서드에서 Cipher를 사용하여 문자열을 해독하는 방법?

Question

안녕하세요 구축이이 방법 암호화가 잘 작동하지만 암호가 바이트를 원하기 때문에 암호 해독이 오류가 발생하고 내가 직접 문자열로 변환 할 수 없습니다

import javax.crypto.Cipher; 
import javax.crypto.spec.SecretKeySpec; 

public class Test { 

    private byte[] encrypted; 

    private String encryptedtext; 
    private String decrypted; 



    public String Encrypt (String pInput) { 


     try { 

     String Input = pInput; 
     String key = "Bar12345Bar12345Bar12345Bar12345"; 

     // Erstelle key and cipher 
     SecretKeySpec aesKey = new SecretKeySpec(key.getBytes(), "AES"); 
     Cipher cipher = Cipher.getInstance("AES"); 

     // Verschlüsselung 
     cipher.init(Cipher.ENCRYPT_MODE, aesKey); 
     byte[] encrypted = cipher.doFinal(Input.getBytes()); 
     encryptedtext = new String(encrypted); 
     System.err.println("encrypted:" + encryptedtext); 


     }catch(Exception e) { 
     e.printStackTrace(); 
     } 

     return encrypted; 
    } 



    public String Decrypt (String pInput) { 


     try { 

      String Input = pInput; 

      String key = "Bar12345Bar12345Bar12345Bar12345"; 

      // Erstelle key and cipher 
      SecretKeySpec aesKey = new SecretKeySpec(key.getBytes(), "AES"); 
      Cipher cipher = Cipher.getInstance("AES"); 

      // Entschlüsselung 
      cipher.init(Cipher.DECRYPT_MODE, aesKey); 
      decrypted = new String(cipher.doFinal(encryptedtext)); // HERE IS THE PROBLEM IT WANT BYTE BUT I WANT TO ENCRYPT FROM A STRING 
      System.err.println("decrypted: " + decrypted); 

     }catch(Exception e) { 
      e.printStackTrace(); 
     } 
     return pInput; 
     } 

} 

Answer 1

바이트 배열 문자열에서 암호화 할 않으며, 어느 쪽도 반대 방향.

import javax.crypto.Cipher; 
import javax.crypto.spec.SecretKeySpec; 
import javax.xml.bind.DatatypeConverter; 

public class stackoverflow_test { 
    private byte[] encrypted; 

    private String encryptedtext; 
    private String decrypted; 

    public String Encrypt(String pInput) { 

     try { 

      String Input = pInput; 
      String key = "Bar12345Bar12345Bar12345Bar12345"; 

      SecretKeySpec aesKey = new SecretKeySpec(key.getBytes(), "AES"); 
      Cipher cipher = Cipher.getInstance("AES"); 

      cipher.init(Cipher.ENCRYPT_MODE, aesKey); 
      byte[] encrypted = cipher.doFinal(Input.getBytes()); 
      //encryptedtext = new String(encrypted); 
      encryptedtext = DatatypeConverter.printBase64Binary(encrypted); 
      System.err.println("encrypted:" + encryptedtext); 

     } catch (Exception e) { 
      e.printStackTrace(); 
     } 

     return encryptedtext; 
    } 

    public String Decrypt(String pInput) { 

     try { 

      String Input = pInput; 

      String key = "Bar12345Bar12345Bar12345Bar12345"; 

      SecretKeySpec aesKey = new SecretKeySpec(key.getBytes(), "AES"); 
      Cipher cipher = Cipher.getInstance("AES"); 

      cipher.init(Cipher.DECRYPT_MODE, aesKey); 
      encrypted = DatatypeConverter.parseBase64Binary(encryptedtext); 
      decrypted = new String(cipher.doFinal(encrypted)); 
      System.err.println("decrypted: " + decrypted); 

     } catch (Exception e) { 
      e.printStackTrace(); 
     } 
     return pInput; 
    } 

    public static void main(String[] ag){ 
     stackoverflow_test test = new stackoverflow_test(); 
     String a = test.Encrypt("Byte cannot directly convert to string"); 
     String b = test.Decrypt(a); 
    } 
} 

결과

encrypted:UmH+3eUagjrRDblxSStArnaktoxTLX+7qvPdwiTO7VggYmYtuXu/Ygww8ZG5SrDz 
decrypted: Byte cannot directly convert to string