링크는 오류 코드를 조회 1052

나는 점점 오전 오류 코드 필드 목록에 1,052 열 FireStationHome 이것은 내가 아래 사용하고있는 코드 쿼리링크는 오류 코드를 조회 1052

에 두 개의 테이블을 동등 조인 할 때 모호 :

SELECT FiremanID, FiremanHomeStation,StationPhone 
FROM FIRE_REPORT AS F, FIRE_STATION AS FS 
WHERE F.FiremanHomeStation = FS.FiremanHomeStation 
AND StationPhone ='703';

포럼을 통해 독서를하는 중 첫 번째 관계를 연결 키로 연결해야한다는 것을 이해하고 있습니다. FiremanHomeStation은 다음 지시 사항을 실행하는 데 필요한 유일한 연결 키입니다.

숫자가 '703'로 시작하는 모든 소방관의 FiremanID, FiremanHomeStation 및 스테이션 전화 번호를 표시하십시오. 나는 다음과 같은

FIRE_REPORT(FireID,Alarms,Address,FiremanID,FiremanName,FiremanPhone,FiremanHomeStation,StationAddress,StationPhone,TruckID,LicensePlate)

규칙을 정규화 한 보이스 커드 방법을 사용하여

각각 불이
에 할당 된 여러 소방관 각 화재 할당 여러 소방차를 가질 수있을 수 있습니다 그것까지
각 소방관 수 여러 화재에 할당 할 수
각 소방차는 sev ERAL이
각 소방관이
각 스테이션이 고유 한 홈 스테이션이 발사
각 스테이션은 하나의 전화 번호

기본 키

FireID, FiremanID, FiremanHomeStation,TruckID 

FireID -> Alarms, Address 
FiremanID -> FiremanName, FiremanPhone, FiremanHomeStation 
FiremanHomeStation -> StationAddress, StationPhone 
TruckID -> LicensePlate

FIRE_REPORT (FireID, FiremanID, FiremanHomeStation을 가지고, TruckID)
화재 (FireID,864,475,524,920,663,210, 알람, 주소)를
FIREMAN_ID (는가, FiremanName, FiremanPhone)이
FIRE_STATION (FiremanHomeStation가 StationAddress, StationPhone)
트럭 (는, LicensePlate)

을 TruckID FiremanID

참조 무결성 제한
FIRE_REPORT에 FireID 화재에 FireID 존재해야
FIRE_REPORT에 FiremanID가 FIRE_REPORT에 FiremanHomeStation 트럭

create schema project_george;<br> 
use project_george;<br> 

CREATE TABLE FIRE (<br> 
    FireID int(3) NOT NULL,<br> 
    Alarms int(1) NOT NULL,<br> 
    Address varChar(25) NOT NULL,<br> 
     CONSTRAINT FIRE_PK PRIMARY KEY(FireID),<br> 
     CONSTRAINT FIRE_FR_FK FOREIGN KEY(FireID)<br> 
     REFERENCES FIRE_REPORT(FireID)<br> 
     ON UPDATE CASCADE<br> 
);<br> 
CREATE TABLE FIREMAN_ID (<br> 
    FiremanID int(3) NOT NULL,<br> 
    FiremanName varchar(25) NOT NULL,<br> 
    FiremanPhone char(10) NOT NULL UNIQUE,<br> 
     CONSTRAINT FI_PK PRIMARY KEY(FiremanID),<br> 
     CONSTRAINT FI_FR_FK FOREIGN KEY(FiremanID)<br> 
     REFERENCES FIRE_REPORT(FiremanID)<br> 
     ON UPDATE CASCADE<br> 
);<br> 
CREATE TABLE FIRE_STATION (<br> 
    FiremanHomeStation varChar(25) NOT NULL UNIQUE,<br> 
    StationAddress varChar(25) NOT NULL,<br> 
    StationPhone char(10) NOT NULL,<br> 
     CONSTRAINT FS_PK PRIMARY KEY(FiremanHomeStation),<br> 
     CONSTRAINT FS_FR_FK FOREIGN KEY(FiremanHomeStation)<br> 
     REFERENCES FIRE_REPORT(FiremanHomeStation)<br> 
     ON UPDATE CASCADE<br> 
);<br> 
CREATE TABLE TRUCK (<br> 
    TruckID int(3) NOT NULL,<br> 
    LicensePlate char(5) NOT NULL UNIQUE,<br> 
      CONSTRAINT TRUCK_PK PRIMARY KEY(TruckID),<br> 
      CONSTRAINT TRUCK_RC_FK FOREIGN KEY(TruckID)<br> 
      REFERENCES FIRE_REPORT(TruckID)<br> 
      ON UPDATE CASCADE<br> 
);<br> 

CREATE TABLE FIRE_REPORT (<br> 
    FireID int(3) NOT NULL,<br> 
    FiremanID int(3) NOT NULL,<br> 
    FiremanHomeStation varChar(25) NOT NULL,<br> 
    TruckID int(3) NOT NULL,<br> 
     CONSTRAINT FR_PK PRIMARY KEY(FireID,FiremanID,FiremanHomeStation,TruckID),<br> 
     CONSTRAINT FR_F_FK FOREIGN KEY (FireID)<br> 
     REFERENCES FIRE(FireID) <br> 
      ON UPDATE CASCADE,<br> 
     CONSTRAINT FR_FID_FK FOREIGN KEY(FiremanID)<br> 
     REFERENCES FIREMAN_ID(FiremanID)<br> 
      ON UPDATE CASCADE,<br> 
     CONSTRAINT FR_FS_FK FOREIGN KEY(FiremanHomeStation)<br> 
     REFERENCES FIRE_STATION(FiremanHomeStation)<br> 
      ON UPDATE CASCADE,<br> 
     CONSTRAINT FR_TRUCK_FK FOREIGN KEY(TruckID)<br> 
     REFERENCES TRUCK(TruckID)<br> 
      ON UPDATE CASCADE<br> 
);<br><br> 

INSERT INTO FIRE VALUES(100, 1, '4025 Medford dr, Annandale VA 22003');<br> 
INSERT INTO FIRE VALUES(101, 2, '7031 Little River Turnpike Suite 5A 
Annandale, VA 22003-5958');<br> 
INSERT INTO FIRE VALUES(102, 3, '7001 Little River Turnpike, Annandale, VA 22003 ');<br> 
INSERT INTO FIRE VALUES(103, 4, '8333 Little River Turnpike Annandale, VA 22003');<br> 
INSERT INTO FIRE VALUES(104, 5, '1600 Pennsylvania Ave NW Washington, DC 20500');<br><br> 

INSERT INTO FIREMAN_ID VALUES(100, 'Guliza Ormuzokova', '703-221-9918');<br> 
INSERT INTO FIREMAN_ID VALUES(101, 'Lex Steele', '703-911-4450');<br> 
INSERT INTO FIREMAN_ID(FiremanID,FiremanName,FiremanPhone) VALUES(102, 'George Putnam', '703-222-9918');<br> 
INSERT INTO FIREMAN_ID VALUES(103, 'Steven Drasner', '571-939-1234');<br> 
INSERT INTO FIREMAN_ID VALUES(104, 'Judy Miller', '571-999-1234');<br> 
INSERT INTO FIREMAN_ID VALUES(105, 'Lily Thai', '703-911-4451');<br><br> 

INSERT INTO FIRE_STATION VALUES('Station 29', '571 Broad st 
Fairfax VA 22030', '703-200-9918');<br> 
INSERT INTO FIRE_STATION VALUES('Station 229', '8914 Little River Turnpike, Fairfax, VA 22031 ', '703-900-4450');<br> 
INSERT INTO FIRE_STATION VALUES('Station 429', '3988 University Dr, Fairfax, VA 22030 ', '571-900-1234');<br><br> 

INSERT INTO TRUCK VALUES(1, 'burn29');<br> 
INSERT INTO TRUCK VALUES(2, 'burn19');<br> 
INSERT INTO TRUCK VALUES(3, 'burn09');<br><br> 

/************I can't figure this on out!!!*** *****/<br> 
SELECT FiremanID, FiremanHomeStation,StationPhone<br> 
FROM FIRE_REPORT AS F, FIRE_STATION AS FS<br> 
WHERE F.FiremanHomeStation = FS.FiremanHomeStation<br> 
AND StationPhone ='703';<br>

에 TruckID 존재해야 FIRE_REPORT에 FIRE_STATION
TruckID에 FiremanHomeStation 존재해야 FIREMAN_ID
에 FiremanID 존재해야

출처

2013-03-25 George Putnam

FiremanHomeStation이 두 테이블에 모두 존재하지만 결과를 원하는 테이블을 지정하지 않았습니다. 이는 모호합니다.

SELECT FiremanID, FS.FiremanHomeStation,StationPhone 
FROM FIRE_REPORT AS F, FIRE_STATION AS FS 
WHERE F.FiremanHomeStation = FS.FiremanHomeStation 
AND StationPhone ='703';

작동합니다

출처

2013-03-25 09:22:11 DessDess

답변

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