작은 하위 목록으로 만들려는 커다란 CSV 파일이 있습니다.이 코드가 작동하지 않는 이유는 무엇입니까? 가치를 분리해야합니까?
유일한 문제는해야하는 일 ... 또는 적어도 일부 물건이 제대로되고
내 문제를 분리하여 데이터를 제대로 분리되지 않는 것입니다 : 나는 데이터가있는 CSV 파일이 그 깊이는 90-3 미터이며, 그 데이터는 그렇게 앞뒤로 갈 것입니다. 나는 최신 파이썬을 사용하고있다.
번호가 다시 증가 할 때마다이를 구분하고 싶습니다.
ex. (깊이) 88, 77, 50, 20, 5, 90, 76, 54, 34, 15,8,4,81,74,62,51,49,30,22,10,8 ... 등 . 90에서 3 사이를 계속 유지합니다.
내가 원하는 것은 90과 3 사이가 될 때마다 데이터를 분리하는 것입니다. 분리되면 해당 목록의 마지막 값과 첫 번째 값을 가져 가고 싶습니다. 전처럼. 90, 76, 54, 34, 15, 8, 4 (여기에서 분리) 81, 74, 62,51, 49, 30, 22, 10, 8)... 등등. ','[ '8.18142', '8.11846', '8.05988', '59 0.4627 :
{ '1': 여기
내 출력된다 : 여기 내 코드 59.4514 ', '57 .6746', '57 .6098 ', '57 .5414', '95 .2296 ', '58 .4541', '58 .3302 ', '58 .2265', '58 .1239 ', '58 .0314', '57 .9405 ', '57 .8496' , '57 .3517 ', '57 .2157', '57 .0934 ', '56 .936', '56 .6363 ', '56 .564', '56 .4287 ', '56 .3106', '56 .2 ', '56 .0877' 55.7858 ', '55 .7612', '55 .0097 ', '54 .87', '55 .8869 ', '55 .8869', '55 .8223 ', '55 .7578', '55 .6933 ', '55 .605', '55 .4949 ', '55 .3858' 86 ', '54 .7385', '54 .6315 ', '54 .5282', '54 .4292 ', '54 .2217', '54 .1127 ', '54 .0037', '53 .8938 ', '53 .7695', '53 .6271 ', '53 .4857' '53 .3437 ', '53 .2254', '53 .1712 ', '53 .12', '53 .0102 ', '52 .9126', '52 .8148 ', '52 .7182', '52 .6207 ', '52 .491', '52 .3561 ',' 52.2277 ', '51 .1141', '51 .0304 ', '50 .9446', '50 .8577 ', '05 .0908', '95 .0908 ',' , '50 .7744 ', '50 .6716', '50 .5655 ', '50 .4625', '50 .3598 ', '50 .2569', '50 .153 ', '50 .0494', '49 .9461 ', '49 .8308', '49 .7058 ', '49 .582' 49.451 ', '49 .3473', '49 .251 ', '49 .1533', '49 .0561 ', '48 .953', '48 .83 ', '48 .7064', '48 .5812 ', '48 .4635', '48 .3852 ', '48 .2998', '48 .2219 ' , '48 .0327 ', '48 .0327', '47 .9221 ', '47 .8114', '47 .7007 ', '47 .5964', '47 .4905 ', '47 .3875', '47 .2895 ', '47 .0424', '46 .9264 ']}#two sets of data that you test with. m = ['9.90203', '9.79947', '9.66876', '9.54503', '9.42167', '9.2977', '9.17321', '9.05162', '8.11487', '8.038', '7.96111', '7.85746', '7.72701', '7.59709', '7.46781', '7.34127', '7.21842', '7.09548', '6.96798', '6.57355', '6.444', '6.32245', '6.23818', '6.15369', '6.04973', '4.63443', '4.49823', '4.36232', '4.21442', '4.0642', '26.5645', '26.4945', '26.4232', '26.3592', '26.2948', '23.418', '23.3667', '23.2756', '23.1856', '22.1849', '22.0822', '22.0191', '21.9671', '21.9154', '21.8641', '20.436', '20.3865', '20.3364', '20.2083', '20.0915', '19.9758', '19.8601', '19.7446', '19.6317', '18.1383', '17.9834', '17.8271', '17.7529', '17.6949', '17.6317', '17.5675', '17.4362', '16.581', '16.4745', '16.378', '16.2562', '16.1471', '16.0222', '15.89', '14.9752', '14.8725', '14.7666', '14.6234', '14.469', '14.3148', '13.7696', '13.6465', '13.5363', '13.4712', '13.4069', '13.3421', '13.2732', '13.1375', '13.0014', '12.4809', '12.3585', '12.2339', '12.121', '12.0116', '11.901', '11.7906', '11.6645', '11.5278', '11.3931', '11.2551', '11.1211', '10.993', '10.8501', '10.7205', '10.6026', '10.4992', '10.3952'] l = ['8.18142', '8.11846', '8.05988', '59.4627', '59.3455', '59.2296', '58.4541', '58.3302', '58.2265', '58.1239', '58.0314', '57.9405', '57.8496', '57.7514', '57.6746', '57.6098', '57.5414', '57.4722', '57.3517', '57.2151', '57.0934', '56.9704', '56.8361', '56.6993', '56.564', '56.4287', '56.3106', '56.2', '56.0877', '55.9782', '55.8869', '55.8223', '55.7578', '55.6933', '55.605', '55.4949', '55.3858', '55.2761', '55.1612', '55.0097', '54.8786', '54.7385', '54.6315', '54.5282', '54.4292', '54.327', '54.2217', '54.1127', '54.0037', '53.8938', '53.7695', '53.6271', '53.4857', '53.3437', '53.2254', '53.1712', '53.12', '53.0679', '53.0102', '52.9126', '52.8148', '52.7182', '52.6207', '52.491', '52.3561', '52.2267', '52.0908', '51.9405', '51.7786', '51.6421', '51.5043', '51.4063', '51.3087', '51.2117', '51.1141', '51.0304', '50.9446', '50.8577', '50.7744', '50.6716', '50.5655', '50.4625', '50.3598', '50.2569', '50.153', '50.0494', '49.9461', '49.8308', '49.7058', '49.582', '49.4583', '49.3473', '49.251', '49.1533', '49.0561', '48.953', '48.83', '48.7064', '48.5812', '48.4635', '48.3852', '48.2998', '48.2219', '48.1428', '48.0327', '47.9221', '47.8114', '47.7007', '47.5964', '47.4905', '47.3875', '47.2847', '47.1595', '47.0424', '46.9264'] group =0 temp = [] splited_list = {} lengh = len(l) for i in range(lengh): if not i == lengh-1: if l[i] > l[i+1]: temp.append(l[i]) else: temp.append(l[i]) group +=1 splited_list.update({str(group):temp}) temp = [] else: if l[i] < l[-2]: temp.append(l[i]) group +=1 splited_list.update({str(group):temp}) break else: group +=1 splited_list.update({str(group):[l[i]]}) break print (splited_list)
다음과 같습니다. 내 원하는 출력 :
{ '1': '8.18142', '8.11846', '8.05988', '2': 59 0.4627 ', '59 0.3455', '59 0.2296 '1958 0.4541' '58 .3302 ', '58 .2265', '58 .1239 ', '58 .0314', '57 .9405 ', '57 .8496', '57 .7546 ', '57 .6746', '57 .5414 ', '57 .4722', '57 .3517 ', '57 .2151 ', '57 .0934', '56 .9704 ', '56 .8361', '56 .6993 ', '56 .548', '56 .4287 ', '56 .3106', '56 .2 ', '56 .0877', '55 .9782 ', '55 .8869', '55 .8223 ' '55 .7578 ', '55 .6933', '55 .605 ', '55.4949', '55 .3858 ', '55 .2716', '55 .1612 ', '55 .0097', '54 .8786 ', '54 .7385', '54 .6315 ', '54 .5282', '54 .4292 ', '54 .327', '54 .2217 ', '54 .1127', '54 .0037 ', '53 .8995', '53 .6271 ', '53 .4857', '53 .3437 ', '53 .2254', '53 .1712 ', '53 .12' '53 .0679 ', '53 .0102', '52 .9126 ', '52 .8148', '52 .7182 ', '52 .6207', '52 .491 ', '52 .3561', '52 .2267 ', '52 .0908', '51 .9405 ', '51 .7786', '51 .6421 ', '51 .5043', '51 .4063 ', '51 .3 '05 ', '50', '', '', '', '', '', '', '', '', '', '', '' '' '' '' , '0494 ', '49 .9461', '49 .8308 ', '49 .7058', '49 .4583 ', '49 .3473', '49 .3473 ', '49 .251', '49 .1533 ', '49 .0561', '48 .953 ', '48 .83' 48.7024 ', '48 .5812', '48 .4635 ', '48 .3852', '48 .2998 ', '48 .2219', '48 .1428 ', '48.0327 ', '47 0.9221', '47 0.8114 ', '47 0.7007', '47 0.5964 ', '47 0.4905', '47 0.3875 ', '47 0.2847', '47 0.1595 ', '47 0.0424'1946 0.9264 ']}
1. 'm'으로 무엇을하고 있습니까? 2. '8.05988'은 문자열을 비교할 때 '5'뒤에 '8'이 오기 때문에 '59 .4627 '보다 큽니다. 3. 각 행은 별도의 사전으로되어 있습니까? 4. 키가 단순한 정수 범위 일 경우 사전을 사용해야하는 이유는 무엇입니까? – TigerhawkT3
1. m은 또 다른 테스트 값 집합입니다. – Adam
2. float을 비교해야합니까? 3. 사전을 만들고, 나중에 각 키의 값으로 목록을 만듭니다 (여기에 표시되지 않음). 4. 확실하지 않습니다 ... 코딩에 익숙하지 않습니다. – Adam