교대 근무 시간 계산

Question

우리가 일하는 도시 중 하나에서 시행되는 새로운 법률이 있습니다. 누군가가 클럭 아웃 할 때까지 최소 11 시간이 있어야합니다. 시간이 11 시간 미만이면 각 사건에 대해 일정 금액을 지불해야합니다. 나는 SQL 서버를 사용하고

2012

나는 각 사람이 교대 사이에 얼마나 많은 시간을 결정할에 도움이 필요합니다. 아래 기록을 토대로 11/14 11:28 pm -> 11/15 8:56 am (9.28 시간) 및 11/29 2:32 am -> 11/29 10:11 am (7.39 시간)

CREATE TABLE #Shift(
    FKEmployeeNumber int, 
    DateOfBusiness datetime, 
    FKStoreId int, 
    EmployeeShiftNumber int, 
    FKJobCodeId int, 
    InHour int, 
    InMinute int, 
    OutHour int, 
    OutMinute int) 

insert into #Shift (FKEmployeeNumber, DateOfBusiness, FKStoreId, EmployeeShiftNumber, FKJobCodeId, InHour, InMinute,OutHour,OutMinute) 
values 
(529251, '11/13/2017', 3013, 0, 1, 8, 1, 16, 24), 
(529251, '11/14/2017', 3013, 0, 1, 15, 21, 23, 28), 
(529251, '11/15/2017', 3013, 0, 1, 8, 56, 15, 58), 
(529251, '11/16/2017', 3013, 0, 1, 14, 59, 20, 54), 
(529251, '11/19/2017', 3013, 0, 1, 12, 40, 19, 42), 
(529251, '11/20/2017', 3013, 1, 1, 8, 28, 23, 47), 
(529251, '11/21/2017', 3013, 0, 1, 15, 31, 23, 30), 
(529251, '11/25/2017', 3013, 0, 1, 10, 26, 18, 13), 
(529251, '11/27/2017', 3013, 0, 1, 9, 58, 18, 27), 
(529251, '11/28/2017', 3013, 0, 1, 14, 59, 2, 32), 
(529251, '11/29/2017', 3013, 0, 1, 10, 11, 17, 13), 
(529251, '11/29/2017', 3013, 1, 1, 17, 16, 17, 25), 
(529251, '11/30/2017', 3013, 0, 1, 15,4, 20, 0), 
(529251, '11/30/2017', 3013, 1, 1, 20, 0, 23, 18), 
(529251, '11/30/2017', 3013, 2, 1, 23, 18, 23, 22), 
(529251, '12/01/2017', 3013, 0, 1, 12, 12, 16, 0) 


Select 
sh.dateofbusiness,sh.fkstoreid,sh.employeeshiftnumber,sh.fkemployeenumber, sh.fkjobcodeid,sh.inHour,sh.InMinute,sh.OutHour,sh.OutMinute 
from #shift sh where sh.dateofbusiness > '11/12/2017' and sh.fkemployeenumber = 529251 
order by sh.FKEmployeeNumber, sh.DateOfBusiness 

Answer 1

여기에 cte 및 자체 조인을 사용하여 일부 날짜 시간을 생성 한 후의 방법이 나와 있습니다. 당신이 2012 년이기 때문에, 당신이 여기 LEAD를 사용하고 row_number() 기능을 제거 할 수 있습니다 또한

if object_id('tempdb..#Shift') is not null 
drop table #Shift 

CREATE TABLE #Shift(
    FKEmployeeNumber int, 
    DateOfBusiness datetime, 
    FKStoreId int, 
    EmployeeShiftNumber int, 
    FKJobCodeId int, 
    InHour int, 
    InMinute int, 
    OutHour int, 
    OutMinute int) 

insert into #Shift (FKEmployeeNumber, DateOfBusiness, FKStoreId, EmployeeShiftNumber, FKJobCodeId, InHour, InMinute,OutHour,OutMinute) 
values 
(529251, '11/13/2017', 3013, 0, 1, 8, 1, 16, 24), 
(529251, '11/14/2017', 3013, 0, 1, 15, 21, 23, 28), 
(529251, '11/15/2017', 3013, 0, 1, 8, 56, 15, 58), 
(529251, '11/16/2017', 3013, 0, 1, 14, 59, 20, 54), 
(529251, '11/19/2017', 3013, 0, 1, 12, 40, 19, 42), 
(529251, '11/20/2017', 3013, 1, 1, 8, 28, 23, 47), 
(529251, '11/21/2017', 3013, 0, 1, 15, 31, 23, 30), 
(529251, '11/25/2017', 3013, 0, 1, 10, 26, 18, 13), 
(529251, '11/27/2017', 3013, 0, 1, 9, 58, 18, 27), 
(529251, '11/28/2017', 3013, 0, 1, 14, 59, 2, 32), 
(529251, '11/29/2017', 3013, 0, 1, 10, 11, 17, 13), 
(529251, '11/29/2017', 3013, 1, 1, 17, 16, 17, 25), 
(529251, '11/30/2017', 3013, 0, 1, 15,4, 20, 0), 
(529251, '11/30/2017', 3013, 1, 1, 20, 0, 23, 18), 
(529251, '11/30/2017', 3013, 2, 1, 23, 18, 23, 22), 
(529251, '12/01/2017', 3013, 0, 1, 12, 12, 16, 0) 


;with cte as(
select 
    FKEmployeeNumber 
    ,DateOfBusiness 
    ,FKStoreId 
    ,EmployeeShiftNumber 
    ,FKJobCodeId 
    ,clockin = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(InHour as varchar),2) + ':' + right('00' + cast(InMinute as varchar),2) as datetime) 
    ,clockout = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(OutHour as varchar),2) + ':' + right('00' + cast(OutMinute as varchar),2) as datetime) 
from 
    #Shift), 

cte2 as(
select *, RN = row_number() over (partition by FKEmployeeNumber order by clockin) 
from cte) 

select 
    c.FKEmployeeNumber 
    ,c.DateOfBusiness 
    ,c.FKStoreId 
    ,c.EmployeeShiftNumber 
    ,c.FKJobCodeId 
    ,c.clockin 
    ,c.clockout 
    ,nexClockInHourDifference = datediff(minute,c.clockout,c2.clockin)/60.0 
from cte2 c 
left join cte2 c2 on c2.FKEmployeeNumber = c.FKEmployeeNumber and c2.RN = c.RN + 1 

drop table #Shift 

, ...

;with cte as(
select 
    FKEmployeeNumber 
    ,DateOfBusiness 
    ,FKStoreId 
    ,EmployeeShiftNumber 
    ,FKJobCodeId 
    ,clockin = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(InHour as varchar),2) + ':' + right('00' + cast(InMinute as varchar),2) as datetime) 
    ,clockout = cast(convert(varchar(10),DateOfBusiness,101) + ' ' + right('00' + cast(OutHour as varchar),2) + ':' + right('00' + cast(OutMinute as varchar),2) as datetime) 
from 
    #Shift) 


select 
    c.FKEmployeeNumber 
    ,c.DateOfBusiness 
    ,c.FKStoreId 
    ,c.EmployeeShiftNumber 
    ,c.FKJobCodeId 
    ,c.clockin 
    ,c.clockout 
    ,nexClockInHourDifference = datediff(minute,c.clockout,lead(c.clockin) over(partition by FKEmployeeNumber order by clockin))/60.0 
from cte c 

drop table #Shift