bash를 사용하여 표시된 것처럼 표준 편차 출력을 테이블에 표시하려면 어떻게합니까? 가 지금의 standar 편차 출력이 표에 나타난 일처럼되지 않습니다 :

Question

이 테이블 출력

Month  CBS  GFS  HR HR Payroll INCV 
       cbs1  gfs1 hr1 hr2 hrm  incv1 

    Standard 
    Deviation 33.00 48.124 29.845 67.934 23.680 12.230 
    (6Mths) 
    2013-07  97  89  14 28 30  4 
    2013-08  58  103  18 6  24  18 
    2013-09  54  110  11 14 25  17 
    2013-10  108 129  17 8  23  18 
    2013-11  52  137  12 8  21  30 
    2013-12  18  84  6  0  13  13 
    2014-01  8  6  1  0  9   3 

아래 내 bash는 스크립트입니다. 도움이 필요합니다.

#!/bin/bash 


    for hostip in `cat $CONFIG ` 
    do 

     name=`echo $hostip|cut -d\: -f1` 
     ip=`echo $hostip|cut -d\: -f2` 
     HTML=/tmp/test.html 
     rm -f $HTML 
     touch $HTML 

     echo "<link rel=\"stylesheet\" type=\"text/css\" href=\"/soc/stylesheet.css\" />" >> $HTML 
     echo "<h2><b>Servers</b></h2>" >> $HTML 
     echo "<table border="1">" >> $HTML 
     echo "<tr><th rowspan="2">Month</th><th>CBS</th><th>GFS</th><th colspan="2">HR</th><th>Payroll</th><th>INCV</th></tr>" >> $HTML 
     echo "<tr><th>cbs1</th><th>gfs1</th><th>hr1</th><th>hr1</th><th>hrm</th><th>incv1</th></tr>" >> $HTML 
    for count in 6 5 4 3 2 1 0 
    do 
     MONTH=`date -d"$count month ago" +"%Y-%m"` 
     CBS=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.22.41 |sort|uniq | wc -l` 
     GFS=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.22.31 |sort|uniq | wc -l` 
     HR1=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.10.1 |sort|uniq | wc -l` 
     HR2=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.21.12 |sort|uniq | wc -l` 
     PAYROLL=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.21.18 |sort|uniq | wc -l` 
     INCV=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.22.71 |sort|uniq | wc -l` 
     echo " <tr><th><a href=/soc/test/archive/tmp/tripwire.$MONTH.html>$MONTH</a><td>$CBS<td>$GFS<td>$HR1<td>$HR2<td>$PAYROLL<td>$INCV</tr>" >>$HTML 
    done 

    echo "</table>" >> $HTML 

이 내 표준 편차 계산

count=0   # Number of data points; global. 
    SC=3   # Scale to be used by bc. three decimal places. 
    E_DATAFILE=90 # Data file error. 

# ----------------- Set data file --------------------- 
    if [ ! -z "$1" ] # Specify filename as cmd-line arg? 
    then 
     datafile="$1" # ASCII text file, 
    else   #+ one (numerical) data point per line! 
     datafile=/home/secmgr/attmrms1/data_tripwire1.sh 
    fi    # See example data file, below. 

    if [ ! -e "$datafile" ] 
    then 
     echo "\""$datafile"\" does not exist!" 
     exit $E_DATAFILE 
    fi 

가에 표시

mean=$(arith_mean); count=$? # Two returns from function! 
    std_dev=$(sd $mean $count) 

    echo 
    #echo "<tr><td>"Number of data points in \""$datafile"\" = $count"<td>$mean<td>$std_dev</tr>" >> $HTML 
    #echo "Arithmetic mean (average) = $mean" 
    #echo "<tr><td>$std_dev</tr>" >> $HTML 
    echo 

난 그냥 원하는 출력을 표준 편차 출력을 표시 평균

arith_mean() 
    { 
     local rt=0   # Running total. 
     local am=0   # Arithmetic mean. 
     local ct=0   # Number of data points. 

     while read value # Read one data point at a time. 
     do 
     rt=$(echo "scale=$SC; $rt + $value" | bc) 
     ((ct++)) 
     done 

     am=$(echo "scale=$SC; $rt/$ct" | bc) 

     echo $am; return $ct # This function "returns" TWO values! 
     # Caution: This little trick will not work if $ct > 255! 
     # To handle a larger number of data points, 
     #+ simply comment out the "return $ct" above. 
    } <"$datafile" # Feed in data file. 

    sd() 
    { 
     mean1=$1 # Arithmetic mean (passed to function). 
     n=$2  # How many data points. 
     sum2=0 # Sum of squared differences ("variance"). 
     avg2=0 # Average of $sum2. 

    sdev=0 # Standard Deviation. 

     while read value # Read one line at a time. 
     do 
     diff=$(echo "scale=$SC; $mean1 - $value" | bc) 
     # Difference between arith. mean and data point. 
     dif2=$(echo "scale=$SC; $diff * $diff" | bc) # Squared. 
     sum2=$(echo "scale=$SC; $sum2 + $dif2" | bc) # Sum of squares. 
     done 

     avg2=$(echo "scale=$SC; $sum2/$n" | bc) # Avg. of sum of squares. 
     sdev=$(echo "scale=$SC; sqrt($avg2)" | bc) # Square root = 
     echo $sdev         # Standard Deviation. 

    } <"$datafile" # Rewinds data file. 

을 계산이다 타 블레어.

Answer 1

첫 번째 bash 스크립트의 경우이 부분을 개선 할 수 있습니다. (GNU awk 필요)

원본 파일은 여러 번 로그 파일을 읽어야합니다.

for count in 6 5 4 3 2 1 0 
    do 
     MONTH=`date -d"$count month ago" +"%Y-%m"` 
     CBS=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.22.41 |sort|uniq | wc -l` 
     GFS=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.22.31 |sort|uniq | wc -l` 
     HR1=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.10.1 |sort|uniq | wc -l` 
     HR2=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.21.12 |sort|uniq | wc -l` 
     PAYROLL=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.21.18 |sort|uniq | wc -l` 
     INCV=`bzcat $LOG/$MONTH*.log.bz2|grep 10.55.22.71 |sort|uniq | wc -l` 
     echo " <tr><th><a href=/soc/test/archive/tmp/tripwire.$MONTH.html>$MONTH</a><td>$CBS<td>$GFS<td>$HR1<td>$HR2<td>$PAYROLL<td>$INCV</tr>" >>$HTML 
    done 

업데이트 나머지 코드를 읽기

for count in {6..0} 
do 
    MONTH=`date -d"$count month ago" +"%Y-%m"` 
    bzcat $LOG/$MONTH*.log.bz2 |awk -v mon=$MONTH '/10.55.22.41/{CBS[$0]} 
    /10.55.22.31/{GFS[$0]} 
    /10.55.10.1/{HR1[$0]} 
    /10.55.21.12/{HR2[$0]} 
    /10.55.21.18/{PAYROLL[$0]} 
    /10.55.22.71/{INCV[$0]} 
    END{printf "<tr><th><a href=/soc/test/archive/tmp/tripwire.%s.html>%s</a><td>%s<td>%s<td>%s<td>%s<td>%s<td>%s</tr>",mon, mon, length(CBS), length(GFS), length(HR1), length(HR2), length(PAYROLL), length(INCV)}' >>$HTML 
done 

합니다. 어떤 부분에 문제가 있음을 보여 주시겠습니까?