0
난 내가 하나 springapp-service.xml을 다음 봄과 최대 절전 모드 4를 구성하는 방법에 대해 3.1
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/jee
http://www.springframework.org/schema/jee/spring-jee-3.1.xsd">
<jee:jndi-lookup id="masterDS" jndi-name="java:jboss/datasources/MySqlDS" />
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="masterDS" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
</beans>
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.1.xsd ">
<bean id="txManager"
class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
<property name="dataSource" ref="masterDS" />
</bean>
<tx:advice id="txAdvice" transaction-manager="txManager">
<tx:attributes>
<tx:method name="get*" read-only="true" propagation="REQUIRED"/>
<tx:method name="*" propagation="REQUIRED"/>
</tx:attributes>
</tx:advice>
<aop:config>
<aop:pointcut expression="execution(* service.*.*(..))"
id="service" />
<aop:advisor advice-ref="txAdvice" pointcut-ref="service" />
</aop:config>
<bean id="contactDAO" class="dao.ContactDAOImpl">
<property name="sessionFactory" ref="sessionFactory"/>
</bean>
<bean id="contactService" class="service.ContactServiceImpl">
<property name="contactDAO" ref="contactDAO"/>
</bean>
</beans>
을 따르처럼 보이는 한 springapp-dao.xml이 그리고 내가 한 DAOImpl
@Repository("ContactDAO")
@Transactional(readOnly = false)
public class ContactDAOImpl implements ContactDAO {
private SessionFactory sessionFactory;
public SessionFactory getSessionFactory() {
return sessionFactory;
}
public void setSessionFactory(SessionFactory sessionFactory) {
this.sessionFactory = sessionFactory;
}
public List<Contacts> listContact() {
return sessionFactory.openSession().createQuery("from Contacts")
.list();
}
}
이 그럼이 제대로 연락처 테이블
0123에 매핑 한 POJO@Entity
@Table(name = "CONTACTS")
public class Contacts {
@Id
@Column(name = "ID")
@GeneratedValue
// The @GeneratedValue annotation says that this value will be determined by
// the datasource, not by the code.
private Integer id;
@Column(name = "FIRSTNAME")
private String firstname;
@Column(name = "LASTNAME")
private String lastname;
@Column(name = "EMAIL")
private String email;
@Column(name = "TELEPHONE")
private String telephone;
@Column(name = "CREATED")
private String created;
그럼 내가 하나 개의 서비스 클래스
@Service
public class ContactServiceImpl implements ContactService {
private ContactDAO contactDAO;
public ContactDAO getContactDAO() {
return contactDAO;
}
public void setContactDAO(ContactDAO contactDAO) {
this.contactDAO = contactDAO;
}
이 ...................
이제 질문이 두 개 있습니다. 먼저 ContactServiceImpl에서 ContactsDAOImpl 및 ContactDAO의 세션 공장을 autowire하려고 할 때 전혀 유선 상태가 아닙니다. 그런 다음 위에서 보았 듯이 setter 및 getters를 사용했습니다. 그런 다음 필요한 종속성을 주입하기 시작했습니다. 지금 내 문제는 내가의 listContact() ContactDAOImpl 방법, (내가 대신의 getConnection의 공장하지만 아무튼 작업에 열려있는 연결을 호출했다 첫째)입니다 때, 는 다음 던졌습니다입니다 exceptiopn
org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.hibernate.hql.internal.ast.QuerySyntaxException: Contacts is not mapped [from Contacts]