WSDL의 wsdl : service definitions가 누락되었습니다.

Question

SOAP 요청을 수행하는 데 ZEEP을 사용하려고합니다.

나는이 요청 가지고 :

def status(request, IP): 
    URL = "http://" + IP + "/Service" 
    session = Session() 
    session.auth = HTTPBasicAuth('username', 'password') 
    client = Client(URL, 
        transport=Transport(session=session), strict=False) 

    response = client.service.Method1(request={'getList'}) 

    return response 

을하지만 WSDL없는 오류를 치고있어 다음 WSDL에서 서비스 정의를.

내가 걸려있어 더 이상 오류 검색을 찾을 수 없습니다. 어떤 아이디어 있니?

컨텍스트에 맞게 편집하십시오. 이것은 작동하는 하드 코딩 요청 내가 zeep 함께 할 노력하고있어 다음 WSDL을 추가

def GetList(session, IP):   

     request = '<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">' 
     request = request + '<soapenv:Header>' 
     request = request + '<session>' + session + '</session>' 
     request = request + ' </soapenv:Header>' 
     request = request + ' <soapenv:Body>' 
     request = request + '<getList/>' 
     request = request + '</soapenv:Body>' 
     request = request + '</soapenv:Envelope>' 

     request = u"""""" + request + """""".format() 

     encoded_request = request.encode('utf-8') 

     headers = {"Host": ""+ IP +"", 
        "Content-Type": "text/xml; charset=UTF-8", 
        "Content-Length": str(len(encoded_request)), 
        "SOAPAction": ""} 

     response = requests.post(url="http://"+ url +"/Service", 
           headers=headers, 
           data=encoded_request, 
           verify=False) 

     return response.content 

편집 2. 당신은 당신의 URL 변수의 끝에 ?wsdl을 추가해야

<?xml version="1.0" encoding="UTF-8"?>  
-<definitions xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:wsdlsoap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:intf="http://xml.apache.org/axis/wsdd/ " xmlns:impl="http://xml.apache.org/axis/wsdd/ " xmlns:apachesoap="http://xml.apache.org/xml-soap" targetNamespace="http://xml.apache.org/axis/wsdd/ ">  
-<wsdl:types>  
-<schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="http://xml.apache.org/axis/wsdd/ ">  
<element type="xsd:anyType" name="parseMessage"/>  
<element type="xsd:anyType" name="parseMessageReturn"/>  
</schema>  
</wsdl:types>  
-<message name="parseMessageResponse">  
<part name="parseMessageReturn" element="impl:parseMessageReturn"/>  
</message>  
-<message name="parseMessageRequest">  
<part name="part" element="impl:parseMessage"/>  
</message>  
-<portType name="MessageHandlerProxy">  
-<operation name="parseMessage">  
<input name="parseMessageRequest" message="impl:parseMessageRequest"/>  
<output name="parseMessageResponse" message="impl:parseMessageResponse"/>  
</operation>  
</portType>  
-<binding type="impl:HandlerProxy" name="ServiceBinding">  
<wsdlsoap:binding transport="http://schemas.xmlsoap.org/soap/http" style="document"/>  
-<operation name="parseMessage">  
<wsdlsoap:operation soapAction=""/>  
-<input name="parseMessageRequest">  
<wsdlsoap:body use="literal" namespace="http://xml.apache.org/axis/wsdd/ "/>  
</input>  
-<output name="parseMessageResponse">  
<wsdlsoap:body use="literal" namespace="http://xml.apache.org/axis/wsdd/ "/>  
</output>  
</operation>  
</binding>  
-<service name="ProxyService">  
-<port name="Service" binding="impl:ServiceBinding">  
<wsdlsoap:address location="http://ip.ip.ip.ip/Service"/>  
</port>  
</service>  
</definitions> 

Answer 1

.

또한 전화 걸기 방법이 올바르지 않습니다. getList에 대한 전화는 다음과 같아야합니다.

def status(request, IP): 
    URL = "http://" + IP + "/Service?wsdl" 
    session = Session() 
    session.auth = HTTPBasicAuth('username', 'password') 
    client = Client(URL, 
        transport=Transport(session=session), strict=False) 

    response = client.service.getList([add the arguments here]) 

    return response