SQL 쿼리

Question

이 내 데이터 프레임의 헤드가 데이터 프레임의 데이터 유형은 STR 다음과 같다

> head(d19_1) 
    SMZ SIZ1_diff SIZ1_base SIZ2_diff SIZ2_base SIZ3_diff SIZ3_base SIZ4_diff SIZ4_base SIZ5_diff SIZ5_base 
1 1  -620  4170  -189  1347  -35  2040  82  1437  244  1533 
2 2  -219  831  -57  255  -4  392   8  282  14  297 
3 3  -426  834  -162  294  -134  379  -81  241  -22  221 
4 4  -481  676  -142  216  -114  267  -50  158  -43  166 
5 5  -233  1711  -109  584  54  913  71  624  74  707 
6 6  -322  1539  -79  512  -50  799  23  532  63  576 
    Total_og Total_base %_SIZ1 %_SIZ2 %_SIZ3 %_SIZ4 %_SIZ5 Total_og Total_base 
1 11980  12648 14.86811 14.03118 1.715686 5.706333 15.916504 11980  12648 
2  2156  2415 26.35379 22.35294 1.020408 2.836879 4.713805  2156  2415 
3  1367  2314 51.07914 55.10204 35.356201 33.609959 9.954751  1367  2314 
4  790  1736 71.15385 65.74074 42.696629 31.645570 25.903614  790  1736 
5  5339  5496 13.61777 18.66438 5.914567 11.378205 10.466761  5339  5496 
6  4362  4747 20.92268 15.42969 6.257822 4.323308 10.937500  4362  4747 

(d19_1) 모습입니다 (rsqlite_send_query 오류)를 작동하지

> str(d19_1) 
'data.frame': 1588 obs. of 20 variables: 
$ SMZ  : int 1 2 3 4 5 6 7 8 9 10 ... 
$ SIZ1_diff : int -620 -219 -426 -481 -233 -322 -176 -112 -34 -103 ... 
$ SIZ1_base : int 4170 831 834 676 1711 1539 720 1396 998 1392 ... 
$ SIZ2_diff : int -189 -57 -162 -142 -109 -79 -12 72 -36 -33 ... 
$ SIZ2_base : int 1347 255 294 216 584 512 196 437 343 479 ... 
$ SIZ3_diff : int -35 -4 -134 -114 54 -50 16 4 26 83 ... 
$ SIZ3_base : int 2040 392 379 267 913 799 361 804 566 725 ... 
$ SIZ4_diff : int 82 8 -81 -50 71 23 36 127 46 75 ... 
$ SIZ4_base : int 1437 282 241 158 624 532 242 471 363 509 ... 
$ SIZ5_diff : int 244 14 -22 -43 74 63 11 143 79 125 ... 
$ SIZ5_base : int 1533 297 221 166 707 576 263 582 429 536 ... 
$ Total_og : int 11980 2156 1367 790 5339 4362 2027 4715 3465 4561 ... 
$ Total_base: int 12648 2415 2314 1736 5496 4747 2168 4464 3278 4375 ... 
$ %_SIZ1 : num 14.9 26.4 51.1 71.2 13.6 ... 
$ %_SIZ2 : num 14 22.4 55.1 65.7 18.7 ... 
$ %_SIZ3 : num 1.72 1.02 35.36 42.7 5.91 ... 
$ %_SIZ4 : num 5.71 2.84 33.61 31.65 11.38 ... 
$ %_SIZ5 : num 15.92 4.71 9.95 25.9 10.47 ... 
$ Total_og : int 11980 2156 1367 790 5339 4362 2027 4715 3465 4561 ... 
$ Total_base: int 12648 2415 2314 1736 5496 4747 2168 4464 3278 4375 ... 

아래 쿼리를 실행하면 아래 오류가 표시되며 이유를 알 수 없습니다. 나는 테이블의 모든 열이없는

쿼리

d20_1 <- sqldf('SELECT *, CASE 
     WHEN SMZ BETWEEN 1 AND 110 THEN "Baltimore City" 
     WHEN SMZ BETWEEN 111 AND 217 THEN "Anne Arundel County" 
     WHEN SMZ BETWEEN 218 AND 405 THEN "Baltimore County" 
     WHEN SMZ BETWEEN 406 AND 453 THEN "Carroll County" 
     WHEN SMZ BETWEEN 454 AND 524 THEN "Harford County" 
     WHEN SMZ BETWEEN 1667 AND 1674 THEN "York County" 
     ELSE 0 
     END Jurisdiction 
     FROM d19_1') 

오류 :

이

Error in rsqlite_send_query(conn@ptr, statement) : 
    table d19_1 has no column named <NA> 

Answer 1

귀하의 코드가 나를 위해 올바르게 작동 : 당신이 있기 때문에

d19_1 <- structure(list(SMZ = 1:6, SIZ1_diff = c(-620L, -219L, -426L, 
-481L, -233L, -322L), SIZ1_base = c(4170L, 831L, 834L, 676L, 
1711L, 1539L), SIZ2_diff = c(-189L, -57L, -162L, -142L, -109L, 
-79L), SIZ2_base = c(1347L, 255L, 294L, 216L, 584L, 512L), SIZ3_diff = c(-35L, 
-4L, -134L, -114L, 54L, -50L), SIZ3_base = c(2040L, 392L, 379L, 
267L, 913L, 799L), SIZ4_diff = c(82L, 8L, -81L, -50L, 71L, 23L 
), SIZ4_base = c(1437L, 282L, 241L, 158L, 624L, 532L), SIZ5_diff = c(244L, 
14L, -22L, -43L, 74L, 63L), SIZ5_base = c(1533L, 297L, 221L, 
166L, 707L, 576L), Total_og = c(11980L, 2156L, 1367L, 790L, 5339L, 
4362L), Total_base = c(12648L, 2415L, 2314L, 1736L, 5496L, 4747L 
), X._SIZ1 = c(14.86811, 26.35379, 51.07914, 71.15385, 13.61777, 
20.92268), X._SIZ2 = c(14.03118, 22.35294, 55.10204, 65.74074, 
18.66438, 15.42969), X._SIZ3 = c(1.715686, 1.020408, 35.356201, 
42.696629, 5.914567, 6.257822), X._SIZ4 = c(5.706333, 2.836879, 
33.609959, 31.64557, 11.378205, 4.323308), X._SIZ5 = c(15.916504, 
4.713805, 9.954751, 25.903614, 10.466761, 10.9375), Total_og.1 = c(11980L, 
2156L, 1367L, 790L, 5339L, 4362L), Total_base.1 = c(12648L, 2415L, 
2314L, 1736L, 5496L, 4747L)), .Names = c("SMZ", "SIZ1_diff", 
"SIZ1_base", "SIZ2_diff", "SIZ2_base", "SIZ3_diff", "SIZ3_base", 
"SIZ4_diff", "SIZ4_base", "SIZ5_diff", "SIZ5_base", "Total_og", 
"Total_base", "X._SIZ1", "X._SIZ2", "X._SIZ3", "X._SIZ4", "X._SIZ5", 
"Total_og.1", "Total_base.1"), row.names = c(NA, -6L), class = "data.frame") 

library(sqldf) 
sqldf('SELECT *, CASE 
     WHEN SMZ BETWEEN 1 AND 110 THEN "Baltimore City" 
     WHEN SMZ BETWEEN 111 AND 217 THEN "Anne Arundel County" 
     WHEN SMZ BETWEEN 218 AND 405 THEN "Baltimore County" 
     WHEN SMZ BETWEEN 406 AND 453 THEN "Carroll County" 
     WHEN SMZ BETWEEN 454 AND 524 THEN "Harford County" 
     WHEN SMZ BETWEEN 1667 AND 1674 THEN "York County" 
     ELSE 0 
     END Jurisdiction 
     FROM d19_1')