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따라서이 프로그램은 3 개의 서로 다른 텍스트 파일을 사용하여 실행 삽입, 셸 및 빠른 정렬을 테스트하기로되어 있지만 이해가되지 않는 이유로 항목 수가 부족한 결과가 표시됩니다. clock()을 사용하여 각 정렬을 실행하는 데 걸리는 시간 (초)과 클럭주기를 표시합니다. 제발, 왜 아무도 작동하지 않는다고 말할 수 있습니까? 나는 곤두박질 친다!쉘, 삽입 및 빠른 정렬을 테스트하는 프로그램의 문제
#include "targetver.h"
#include <time.h>
#include <stdio.h>
#include <dos.h>
#include <iomanip>
#include <fstream>
#include <string>
#include <stdio.h>
#include <tchar.h>
#include <queue>
#include <stack>
#include <vector>
#include<iostream>
#include<cstdio>
#include<sstream>
#include<algorithm>
using namespace std;
// insertion sort function
void insertionSort(vector<int> arr, int n)
{
int i, key, j;
for (i = 1; i < n; i++)
{
key = arr[i];
j = i - 1;
/* Move elements of arr[0..i-1], that are
greater than key, to one position ahead
of their current position */
while (j >= 0 && arr[j] > key)
{
arr[j + 1] = arr[j];
j = j - 1;
}
arr[j + 1] = key;
}
}
// shell sort function
void shellSort(vector<int> arr, int n)
{
// Start with a big gap, then reduce the gap
for (int gap = n/2; gap > 0; gap /= 2)
{
// Do a gapped insertion sort for this gap size.
// The first gap elements a[0..gap-1] are already in gapped order
// keep adding one more element until the entire array is
// gap sorted
for (int i = gap; i < n; i += 1)
{
// add a[i] to the elements that have been gap sorted
// save a[i] in temp and make a hole at position i
int temp = arr[i];
// shift earlier gap-sorted elements up until the correct
// location for a[i] is found
int j;
for (j = i; j >= gap && arr[j - gap] > temp; j -= gap)
arr[j] = arr[j - gap];
// put temp (the original a[i]) in its correct location
arr[j] = temp;
}
}
}
// function that swaps two elements
void swap(int* a, int* b)
{
int t = *a;
*a = *b;
*b = t;
}
/* This function takes last element as pivot, places
the pivot element at its correct position in sorted
array, and places all smaller (smaller than pivot)
to left of pivot and all greater elements to right
of pivot */
int partition(vector<int> arr, int low, int high)
{
int pivot = arr[high]; // pivot
int i = (low - 1); // Index of smaller element
for (int j = low; j <= high - 1; j++)
{
// If current element is smaller than or
// equal to pivot
if (arr[j] <= pivot)
{
i++; // increment index of smaller element
swap(&arr[i], &arr[j]);
}
}
swap(&arr[i + 1], &arr[high]);
return (i + 1);
}
/* The main function that implements QuickSort
arr --> Array to be sorted,
low --> Starting index,
high --> Ending index */
void quickSort(vector<int> arr, int low, int high)
{
if (low < high)
{
/* pi is partitioning index, arr[p] is now
at right place */
int pi = partition(arr, low, high);
// Separately sort elements before
// partition and after partition
quickSort(arr, low, pi - 1);
quickSort(arr, pi + 1, high);
}
}
// print array function
void printArray(vector<int> arr)
{
int z = arr.size();
int i;
for (i = 0; i < z; i++)
printf("%d ", arr[i]);
printf("n");
}
int main()
{
int max = 10000000;
vector<int> arr;
arr.reserve(max);
double start, end, elapsed_clock, elapsed_time;
int low, high, n;
string name;//holds first file name entered by user
ifstream fin;
cout << "Please enter the file name you wish to read from: ";//asks user for file name
getline(cin, name);//gets file name
fin.open(name);//opens file with set file name
if (fin.fail())//run if file name is incorrect or fails to load
{
cout << "Error opening " << name << "\n";//print error and file name
}
else
{
cout << "\nFile opened successfully, please wait." << endl;
// holds data read from file
int theData;
do // loop reads file till end
{
fin >> theData;
if (fin.good())
{
arr.push_back(theData);
}
//if read failed, check to see if file end was cause, otherwise print message and close
else if (!fin.eof())
{
cout << "\nThe file could not be read" << endl;
}
//runs while data being read
} while (!fin.eof());
}
fin.close();
n = sizeof(arr)/sizeof(arr[0]);
start = clock();
insertionSort(arr, n);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Insertion Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
start = clock();
shellSort(arr, n);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Shell Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
start = clock();
quickSort(arr, 0, n - 1);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Quick Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
printArray(arr);
cout << endl;//space
cout << "Please enter the file name you wish to read from: ";//asks user for file name
getline(cin, name);//gets file name
fin.open(name);//opens file with set file name
if (fin.fail())//run if file name is incorrect or fails to load
{
cout << "Error opening " << name << "\n";//print error and file name
}
else
{
cout << "\nFile opened successfully, please wait." << endl;
// holds data read from file
int theData;
do // loop reads file till end
{
fin >> theData;
if (fin.good())
{
arr.push_back(theData);
}
//if read failed, check to see if file end was cause, otherwise print message and close
else if (!fin.eof())
{
cout << "\nThe file could not be read" << endl;
}
//runs while data being read
} while (!fin.eof());
}
fin.close();
n = sizeof(arr)/sizeof(arr[0]);
start = clock();
insertionSort(arr, n);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Insertion Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
start = clock();
shellSort(arr, n);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Shell Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
start = clock();
quickSort(arr, 0, n - 1);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Quick Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
printArray(arr);
cout << endl;//space
cout << "Please enter the file name you wish to read from: ";//asks user for file name
getline(cin, name);//gets file name
fin.open(name);//opens file with set file name
if (fin.fail())//run if file name is incorrect or fails to load
{
cout << "Error opening " << name << "\n";//print error and file name
}
else
{
cout << "\nFile opened successfully, please wait." << endl;
// holds data read from file
int theData;
do // loop reads file till end
{
fin >> theData;
if (fin.good())
{
arr.push_back(theData);
}
//if read failed, check to see if file end was cause, otherwise print message and close
else if (!fin.eof())
{
cout << "\nThe file could not be read" << endl;
}
//runs while data being read
} while (!fin.eof());
}
fin.close();
n = sizeof(arr)/sizeof(arr[0]);
start = clock();
insertionSort(arr, n);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Insertion Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
start = clock();
shellSort(arr, n);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Shell Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
start = clock();
quickSort(arr, 0, n - 1);
end = clock();
elapsed_clock = end - start;
elapsed_time = ((end - start)/CLK_TCK);
cout << "Quick Sort\t: " << arr.size() << " items" << " " << elapsed_clock << " ticks" << " " << elapsed_time << " sec\n";
printArray(arr);
cout << endl;//space
system("Pause");//waits for user input
return 0;
}
시도해 보니 아무 것도하지 않습니다. elapsed_clock (함수가 완료 될 때까지의 틱 수) 및 elapsed_time (함수가 완료되는 데 걸리는 초 수)은 여전히 반환되지 않습니다. –
이 줄을 수정해야합니다 (이 함수는 n = sizeof (arr)/sizeof (arr [0]);', 이제 'n'의 값은 항상 동일합니다 (벡터의 크기는을 int의 크기로 나눕니다). 'n' 대신에 주어진 정렬 함수를 호출 할 때'arr.size()'를 사용하십시오. –
rafix07
'sizeof (arr)'의 값은 구현 및 컴퓨터 아키텍처에 따라 다르며 12,16, .. 24 일 수 있으므로 'n'값은 항상 작습니다. 'sizeof (arr)/sizeof (arr [0])'를 사용하여 C 스타일의 배열에 대한 배열의 숫자를 얻을 수 있습니다. – rafix07