Oracle SQL (BI Publisher)에서 날짜/시간 출력

Question

oracle BI Publisher에서 문자열에 (hr : min : 초)없이 날짜 (일/월/년)를 출력하려고합니다. 형식을 지정하는 여러 가지 방법을 시도했지만 아무 것도 작동하지 않는 것 같습니다.

DATE_OF_AVG       DAILY_AVG_VALUE 
-------------------------------  --------------- 
(2017-02-28T00:00:00.000+00:00)    100 
(2017-02-27T00:00:00.000+00:00)    99 
(2017-02-26T00:00:00.000+00:00)    99 
(2017-02-25T00:00:00.000+00:00)    99 
(2017-02-22T00:00:00.000+00:00)    99 
(2017-02-21T00:00:00.000+00:00)    94 
(2017-02-20T00:00:00.000+00:00)    99 
(2017-02-19T00:00:00.000+00:00)    99 
(2017-02-18T00:00:00.000+00:00)    100 

예상 출력 : 어떤 도움을 크게 감상 할 수

DATE_OF_AVG DAILY_AVG_VALUE 
----------- --------------- 
28-FEB-17   100 
27-FEB-17   99 
26-FEB-17   99 
25-FEB-17   99 
22-FEB-17   99 
21-FEB-17   94 
20-FEB-17   99 
19-FEB-17   99 
18-FEB-17   100 

select "DATA_POINT_DAILY_AVG"."DATE_OF_AVG" as "DATE_OF_AVG", 
    "DATA_POINT_DAILY_AVG"."VALUE" as "DAILY_AVG_VALUE" 
from "TEST"."CALCULATED_DATA_POINT" "CALCULATED_DATA_POINT", 
    "TEST"."DATA_POINT_DAILY_AVG" "DATA_POINT_DAILY_AVG" 
where "DATA_POINT_DAILY_AVG"."CALCULATED_DATA_POINT_ID"="CALCULATED_DATA_POINT"."ID" 
    and "DATA_POINT_DAILY_AVG"."SITE_ID" in ('123abc') 
    and "DATA_POINT_DAILY_AVG"."DATE_OF_AVG" between ('01-FEB-17') and ('28-FEB-17') 
    and "CALCULATED_DATA_POINT"."NAME" ='test_uptime' 
order by "DATA_POINT_DAILY_AVG"."DATE_OF_AVG" DESC; 

여기 내 전류 출력입니다 : 여기 내 코드입니다.

감사합니다.

Answer 1

to_char (date_col, 'DD-MON-YY')