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이것은 작성한 코드이지만 새로운 내장 기능은 작동하지 않는 것 같습니다. 오류가 발생합니다.Jena에 내장 된 사용자 정의
Exception in thread "main" com.hp.hpl.jena.reasoner.rulesys.impl.LPRuleSyntaxException: Syntax error in backward rule: matematica Unknown builtin operation mysum
어디서 오류가 발생하는지 알려주실 수 있습니까? 난 당신이 점점 예외를 복제 할 수 없습니다,
package JenaRules;
import java.io.BufferedReader;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.List;
import org.semanticweb.owlapi.model.OWLOntologyCreationException;
import org.semanticweb.owlapi.model.OWLOntologyStorageException;
import com.hp.hpl.jena.graph.Node;
import com.hp.hpl.jena.query.Query;
import com.hp.hpl.jena.query.QueryExecution;
import com.hp.hpl.jena.query.QueryExecutionFactory;
import com.hp.hpl.jena.query.QueryFactory;
import com.hp.hpl.jena.query.ResultSet;
import com.hp.hpl.jena.query.ResultSetFormatter;
import com.hp.hpl.jena.rdf.model.InfModel;
import com.hp.hpl.jena.rdf.model.Model;
import com.hp.hpl.jena.rdf.model.ModelFactory;
import com.hp.hpl.jena.rdf.model.Resource;
import com.hp.hpl.jena.reasoner.Reasoner;
import com.hp.hpl.jena.reasoner.rulesys.*;
import com.hp.hpl.jena.reasoner.rulesys.builtins.BaseBuiltin;
import com.hp.hpl.jena.util.FileManager;
import com.hp.hpl.jena.vocabulary.RDFS;
import com.hp.hpl.jena.vocabulary.ReasonerVocabulary;
public class RulesOntology_MT {
public static void main(String[] args) throws OWLOntologyStorageException,
OWLOntologyCreationException, IOException {
BuiltinRegistry.theRegistry.register(new BaseBuiltin() {
@Override
public String getName() {
return "mysum";
}
@Override
public int getArgLength() {
return 2;
}
@Override
public boolean bodyCall(Node[] args, int length, RuleContext context) {
checkArgs(length, context);
BindingEnvironment env = context.getEnv();
Node n1 = getArg(0, args, context);
Node n2 = getArg(1, args, context);
if (n1.isLiteral() && n2.isLiteral()) {
Object v1 = n1.getLiteralValue();
Object v2 = n2.getLiteralValue();
Node sum = null;
if (v1 instanceof Number && v2 instanceof Number) {
Number nv1 = (Number)v1;
Number nv2 = (Number)v2;
int sumInt = nv1.intValue()+nv2.intValue();
sum = Util.makeIntNode(sumInt);
return env.bind(args[2], sum);
}
}
return false;
}
});
// NON SERVE
// final String exampleRuleString2 =
// "[mat1: equal(?s ?p)\n\t-> print(?s ?p ?o),\n\t (?s ?p ?o)\n]"+
// "";
final String exampleRuleString =
"[matematica:"+
"(?p http://www.semanticweb.org/prova_rules_M#totale_crediti ?x)"+
" -> " +
"(?p rdf:type http://www.semanticweb.org/prova_rules_M#:Persona)"+
"(?e rdf:type http://www.semanticweb.org/prova_rules_M#:Esame)"+
"(?p http://www.semanticweb.org/prova_rules_M#:haSostenutoEsameDi ?e)"+
"(?e http://www.semanticweb.org/prova_rules_M/persona#crediti_esame ?cr)"+
"mysum(?cr,2)"+
"]";
System.out.println(exampleRuleString);
/* I tend to use a fairly verbose syntax for parsing out my rules when I construct them
* from a string. You can read them from whatever other sources.
*/
final List<Rule> rules;
try(final BufferedReader src = new BufferedReader(new InputStreamReader(new ByteArrayInputStream(exampleRuleString.getBytes())))) {
rules = Rule.parseRules(Rule.rulesParserFromReader(src));
}
/* Construct a reasoner and associate the rules with it */
// create an empty non-inferencing model
GenericRuleReasoner reasoner = (GenericRuleReasoner) GenericRuleReasonerFactory.theInstance().create(null);
reasoner.setRules(rules);
/* Create & Prepare the InfModel. If you don't call prepare, then
* rule firings and inference may be deferred until you query the
* model rather than happening at insertion. This can make you think
* that your Builtin is not working, when it is.
*/
InfModel infModel = ModelFactory.createInfModel(reasoner, ModelFactory.createDefaultModel());
infModel.prepare();
infModel.createResource(RDFS.Class);
//write down the result in RDFXML form
infModel.write(System.out);
}
}
"*하지만 새로운 내장 기능이 작동하지 않는 것 같습니다. 인식되지 않습니다. *"이 문제에 대한 설명을 이해하지 못합니다. 무슨 문제가 보이니? 컴파일 오류? 런타임 오류? 예기치 않은 결과가 나왔습니까? –
내 오류 : 스레드 "main"의 예외 com.hp.hpl.jena.reasoner.rulesys.impl.LPRuleSyntaxException : 역순 규칙의 구문 오류 : matematica 알 수없는 기본 제공 작업 mysum. 추론자를 설정하여 새로운 내장 기능을 인식 할 수있게하는 방법을 모르겠습니다. – user3563844