gridview 애플리케이션을 만들었으며 json에서 제공 한 URL이있는 이미지의 경로를 얻습니다. JSON은 이미지의 URL 경로를 많이 제공하며 모든 URL에는 잘못된 경로가 있습니다.android에서 잘못된 URL 오류를 throw하는 방법
어떻게하면 잘못된 URL을 던져서 다른 URL을 가져올 수 있습니까?
전체 코드 MainActivity. CountryJSONParser
/** AsyncTask to download and load an image in ListView */
private class ImageLoaderTask extends AsyncTask<HashMap<String, Object>, Void, HashMap<String, Object>>{
@Override
protected HashMap<String, Object> doInBackground(HashMap<String, Object>... hm) {
InputStream iStream=null;
String imgUrl;
String frameUrl;
imgUrl = (String) hm[0].get("photo_path");
frameUrl = (String) hm[0].get("frame_path");
int position = (Integer) hm[0].get("position");
URL url;
URL urlFrame;
try {
url = new URL(imgUrl);
urlFrame = new URL(frameUrl);
// Creating an http connection to communicate with url
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
// Connecting to url
urlConnection.connect();
// Reading data from url
iStream = urlConnection.getInputStream();
// Getting Caching directory
File cacheDirectory = getBaseContext().getCacheDir();
// Temporary file to store the downloaded image
File tmpFile = new File(cacheDirectory.getPath() + "/wpta_"+position+".png");
// The FileOutputStream to the temporary file
FileOutputStream fOutStream = new FileOutputStream(tmpFile);
// Creating a bitmap from the downloaded inputstream
Bitmap b = BitmapFactory.decodeStream(iStream);
// Writing the bitmap to the temporary file as png file
b.compress(Bitmap.CompressFormat.PNG,100, fOutStream);
// Flush the FileOutputStream
fOutStream.flush();
//Close the FileOutputStream
fOutStream.close();
// Create a hashmap object to store image path and its position in the listview
HashMap<String, Object> hmBitmap = new HashMap<String, Object>();
// Storing the path to the temporary image file
hmBitmap.put("photo",tmpFile.getPath());
hmBitmap.put("frame", tmpFile.getPath());
// Storing the position of the image in the listview
hmBitmap.put("position",position);
// Returning the HashMap object containing the image path and position
return hmBitmap;
}catch (Exception e) {
e.printStackTrace();
}
return null;
}
은 자신의 예외'InvalidURLException' 쓰기 적절한 (그리고 아마도 그것을 잡을) – keyser