SQL 피벗 테이블은 오전에

Question

나는이 결과를

1 http://img853.imageshack.us/img853/8112/sqltotal.jpg

유일한 예를 달성하기 위해 노력하고

 create table test4(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int) 
      insert into test4 values ('Austin', 'African-American', 'male', 21) 
      insert into test4 values ('Austin', 'Asian', 'female', 22) 
      insert into test4 values ('Austin', 'Caucasian', 'male', 23) 
      insert into test4 values ('Austin', 'Hispanic', 'female', 24) 
      insert into test4 values ('Austin', 'African-American', 'Unknown', 25) 
      insert into test4 values ('Austin', 'Asian', 'male', 26) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 27) 
      insert into test4 values ('Austin', 'Hispanic', 'Unknown', 28) 
      insert into test4 values ('Austin', 'Asian', 'male', 29) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 31) 
      insert into test4 values ('Dallas', 'Hispanic', 'Unknown', 32) 
      insert into test4 values ('Dallas', 'African-American', 'male', 33) 
      insert into test4 values ('Dallas', 'Asian', 'female', 34) 
      insert into test4 values ('Dallas', 'Caucasian', 'Unknown', 35) 
      insert into test4 values ('Dallas', 'Hispanic', 'male', 500) 
      insert into test4 values ('Dallas', 'African-American', 'female', 36) 
      insert into test4 values ('Dallas', 'Asian', 'Unknown', 37) 
      insert into test4 values ('Dallas', 'Caucasian', 'male', 38) 
      insert into test4 values ('Dallas', 'Hispanic', 'female', 39) 
      insert into test4 values ('Dallas', 'African-American', 'Unknown', 41) 
      insert into test4 values ('Houston', 'Asian', 'male', 42) 
      insert into test4 values ('Houston', 'Caucasian', 'female', 43) 
      insert into test4 values ('Houston', 'Hispanic', 'Unknown', 44) 
      insert into test4 values ('Houston', 'African-American', 'male', 45) 
      insert into test4 values ('Houston', 'Asian', 'female', 46) 
      insert into test4 values ('Houston', 'Caucasian', 'Unknown', 47) 
      insert into test4 values ('Houston', 'Hispanic', 'male', 48) 
      insert into test4 values ('Houston', 'African-American', 'female', 49) 
      insert into test4 values ('Houston', 'Asian', 'Unknown', 51) 
      insert into test4 values ('Houston', 'Caucasian', 'male', 52); 

      WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM test4 AS A 
      ) 
      SELECT * 
      FROM T 
      PIVOT(COUNT(age_range_race) FOR age_range_race 
       IN(
        [20-30_African-American], 
        [20-30_Asian], 
        [20-30_Caucasian], 
        [20-30_Hispanic], 
        [31-40_African-American], 
        [31-40_Asian], 
        [31-40_Caucasian], 
        [31-40_Hispanic], 
        [41-50_African-American], 
        [41-50_Asian], 
        [41-50_Caucasian], 
        [41-50_Hispanic] 
       ) 
      ) AS P 

이 피벗 테이블에 행과 열 합계를 추가하려고 합계 Google에서 SQL 2000 용으로 작성된 저장 프로 시저를 찾을 수 있습니다. 도와주세요! 사전

Answer 1

여기

당신이 시도. 스크립트가

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
into #tmp_result 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P 

select * 
from #tmp_result 
union all 
select 'Grand Total','',SUM([20-30_African-American]), SUM([20-30_Asian]), SUM([20-30_Caucasian]), SUM([20-30_Hispanic]),SUM([31-40_African-American]), SUM([31-40_Asian]), SUM([31-40_Caucasian]), SUM([31-40_Hispanic]),SUM([41-50_African-American]), SUM([41-50_Asian]), SUM([41-50_Caucasian]),SUM([41-50_Hispanic]), sum(Total) 
from #tmp_result 

Answer 2

다음과 같이 시도하십시오 감사드립니다 ..

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P