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제 이해를위한 임시 해결 방법과 깊이 관련 답변을 제공해주십시오. 나는 signup.html과 /users/js/signup.js와 사용자 /라는 디렉토리를/가지고 내가 PHP를 사용하여 내 홈 페이지다른 디렉토리에 양식 제출을 위해 PHP 함수 include_once()를 사용하는 방법?
을 /users/signup.php : 다음 경우 include_once 문 (signup.html를) 및 등록 버튼을 클릭하면 index.php 디렉토리의 디렉토리가 사용됩니다.
signup.html 파일의 경로에 효과적으로 포함 할 수있는 함수가 있습니까?
/public_html/index.php
/public_html/users/signup.html
<!DOCTYPE html>
<html>
<head>
<title>Sign Up</title>
<meta charset="UTF-8"><br>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-alpha.6/css/bootstrap.min.css" integrity="sha384-rwoIResjU2yc3z8GV/NPeZWAv56rSmLldC3R/AZzGRnGxQQKnKkoFVhFQhNUwEyJ" crossorigin="anonymous">
<script src="https://code.jquery.com/jquery-3.1.1.slim.min.js" integrity="sha384-A7FZj7v+d/sdmMqp/nOQwliLvUsJfDHW+k9Omg/a/EheAdgtzNs3hpfag6Ed950n" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/tether/1.4.0/js/tether.min.js" integrity="sha384-DztdAPBWPRXSA/3eYEEUWrWCy7G5KFbe8fFjk5JAIxUYHKkDx6Qin1DkWx51bBrb" crossorigin="anonymous"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-alpha.6/js/bootstrap.min.js" integrity="sha384-vBWWzlZJ8ea9aCX4pEW3rVHjgjt7zpkNpZk+02D9phzyeVkE+jo0ieGizqPLForn" crossorigin="anonymous"></script>
</head>
<div class="container py-5">
<div class="row">
<div class="col-md-12">
<h2 class="text-center text-white mb-4">Bootstrap 4 Login Form</h2>
<div class="row">
<div class="col-md-6 mx-auto">
<span class="anchor" id="formLogin"></span>
<div id="signupStatus"></div>
<!--Card Sign Up !-->
<div class="card rounded-0">
<div class="card-header">
<h3 class="mb-0">Sign Up</h3>
</div>
<div class="card-body">
<form id="signupForm" class="form" role="form" autocomplete="off" style="overflow: hidden">
<div class="signup form-group">
<label for="username">Username</label>
<input type="text" id="username" class="form-control form-control-lg rounded-0" name="username" placeholder="username"/>
</div>
<div class="signup form-group">
<label for="email">Email</label>
<input id="email" class="form-control form-control-lg rounded-0" type="email" name="email" placeholder="email"/>
</div>
<div class="signup form-group">
<label for="password">Password</label>
<input id="password" class="form-control form-control-lg rounded-0" type="password" name="password" placeholder="password"/>
</div>
<div class="signup"><input class="btn btn-success btn-lg float-right" type="button" id="signup" value="Sign up"/></div>
<div class="signup"><a href="http://woofwarrior.com/users/login.html">...already a user?</a></div>
</form>
</div>
</div>
</div>
</div>
</div>
</div>
</div>
<script type="text/javascript">
users_dir = 'http://'+window.location.hostname+'/users/';
document.getElementById("signup").onclick = function(){
var httpRequest;
httpRequest = new XMLHttpRequest();
if (!httpRequest) {
console.log('Cannot create an XMLHTTP instance');
return false;
}else{
httpRequest.onreadystatechange = alertContents;
var formElement = document.getElementById('signupForm');
var formData = new FormData(formElement);
httpRequest.open("POST", users_dir+'signup.php');
//console.log(formData);
httpRequest.send(formData);
}
function alertContents() {
if (httpRequest.readyState === XMLHttpRequest.DONE) {
//console.log(httpRequest.status);
if (httpRequest.status === 200) {
//console.log("test123");
var data = JSON.parse(httpRequest.responseText);
//console.log(data);
document.getElementById('signupStatus').innerHTML = data;
}else{
console.log('There was a problem with the request.');
}
}
}
}
나는 당신이 무엇을 요구하고 있는지 이해하지 못합니다. – GrumpyCrouton