여러 파일을 PHP로 작성하는 방법

Question

저는 PHP로 초보자이며 이제는 PHP로 프로젝트를하고 있습니다. 이미지를 업로드하고 싶습니다 (최대 4 개의 이미지 파일 만) . 다음 코드를 사용하여 이미지를 업로드했습니다.

<?php if(isset($_POST['submit'])) { 
    $count=count($_FILES["images"]["name"]); 


for($i=0;$i<$count;$i++) {  if ((($_FILES["images"]["type"][$i] == "image/gif") || ($_FILES["images"]["type"][$i] == "image/jpeg") || ($_FILES["images"]["type"][$i] == "image/pjpeg")) && ($_FILES["images"]["size"][$i] < 100000)) { 

if ($_FILES["images"]["error"][$i] > 0) { echo "File Error : " . $_FILES["images"]["error"][$i] . "<br />"; } else { echo "Upload File Name: " . $_FILES["images"]["name"][$i] . "<br />"; echo "File Type: " . $_FILES["images"]["type"][$i] . "<br />"; echo "File Size: " . ($_FILES["images"]["size"][$i]/1024) . " Kb<br />"; 


    if (file_exists("public/images/".$_FILES["images"]["name"][$i])) { echo "<b>".$_FILES["images"]["name"][$i] . " already exists. </b>"; } else { 
    move_uploaded_file($_FILES["images"]["tmp_name"][$i] ,"public/images/".    $_FILES["images"]["name"][$i]); 
    echo "Stored in: " . "public/images/" . $_FILES["images"]["name"][$i] ."<br />"; ?> Uploaded File:<br> <img src="public/images/<?php echo $_FILES["images"]["name"][$i] ; ?>" alt="Image path Invalid" > <?php } } }else { echo "Invalid file detail ::<br> file type ::".$_FILES["images"]["type"][$i] ." , file size::: ".$_FILES["images"]["size"][$i] ; } } }?> 

Answer 1

먼저 들여 쓰기를 배우십시오.

개수가 잘못되었습니다. $_FILES['images']['name'] 크기를 계산 중이지만, 얼마나 많은 숫자가 $_FILES['images']인지 계산해야합니다. 그래서 ([$i] 키의 새로운 위치에주의)과 같이 코드를 변경 :

<?php 
if (isset($_POST['submit'])) { 
    $count = count($_FILES["images"]); 
    for ($i = 0; $i < $count; $i++) { 
     if ((($_FILES["images"][$i]["type"] == "image/gif") || ($_FILES["images"][$i]["type"] == "image/jpeg") || ($_FILES["images"][$i]["type"] == "image/pjpeg")) && ($_FILES["images"][$i]["size"] < 100000)) { 
      if ($_FILES["images"][$i]["error"] > 0) { 
       echo "File Error : " . $_FILES["images"][$i]["error"] . "<br />"; 
      } else { 
       echo "Upload File Name: " . $_FILES["images"][$i]["name"] . "<br />"; 
       echo "File Type: " . $_FILES["images"][$i]["type"] . "<br />"; 
       echo "File Size: " . ($_FILES["images"][$i]["size"]/1024) . " Kb<br />"; 
       if (file_exists("public/images/" . $_FILES["images"][$i]["name"])) { 
        echo "<b>" . $_FILES["images"][$i]["name"] . " already exists. </b>"; 
       } else { 
        move_uploaded_file($_FILES["images"][$i]["tmp_name"], "public/images/" . $_FILES["images"][$i]["name"]); 
        echo "Stored in: " . "public/images/" . $_FILES["images"][$i]["name"] . "<br />"; 
        ?> Uploaded File: 
        <br> 
        <img src="public/images/ 
        <?php echo $_FILES["images"][$i]["name"]; ?>" alt="Image path Invalid" > 
       <?php 
       } 
      } 
     } else { 
      echo "Invalid file detail ::<br> file type ::" . $_FILES["images"][$i]["type"] . " , file size::: " . $_FILES["images"][$i]["size"]; 
     } 
    } 
}?> 

을이 코드가 HTML이 같은 것입니다 가정 작동합니다

<input type="file" name="images[]" /> 
<input type="file" name="images[]" /> 
<input type="file" name="images[]" /> 
<input type="file" name="images[]" /> 
<input type="file" name="images[]" /> 
<input type="file" name="images[]" />