나는
api_exception_subscriber:
class: AppBundle\EventListener\ApiExceptionSubscriber
arguments: ['%kernel.debug%', '@api.response_factory', '@logger']
tags:
- { name: kernel.event_subscriber }
api.response_factory:
class: AppBundle\Api\ResponseFactory
내 응답 공장처럼 내 services.yml에에게 다음과 같은 방법으로, 해결 :
<?php
namespace AppBundle\Api;
use Symfony\Component\HttpFoundation\JsonResponse;
class ResponseFactory
{
public function createResponse(ApiProblem $apiProblem)
{
$data = $apiProblem->toArray();
$response = new JsonResponse(
$data,
$apiProblem->getStatusCode()
);
$response->headers->set('Content-Type', 'application/json');
return $response;
}
}
과 API를 subscriper 클래스
<?php
namespace AppBundle\EventListener;
use AppBundle\Api\ApiProblem;
use AppBundle\Api\ApiProblemException;
use AppBundle\Api\ResponseFactory;
use Psr\Log\LoggerInterface;
use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent;
use Symfony\Component\HttpKernel\KernelEvents;
use Symfony\Component\HttpFoundation\JsonResponse;
use Symfony\Component\HttpKernel\Exception\HttpExceptionInterface;
class ApiExceptionSubscriber implements EventSubscriberInterface
{
private $debug;
private $responseFactory;
private $logger;
public function __construct($debug, ResponseFactory $responseFactory, LoggerInterface $logger)
{
$this->debug = $debug;
$this->responseFactory = $responseFactory;
$this->logger = $logger;
}
public function onKernelException(GetResponseForExceptionEvent $event)
{
// only reply to /api URLs
if (strpos($event->getRequest()->getPathInfo(), '/api') !== 0) {
return;
}
$e = $event->getException();
$statusCode = $e instanceof HttpExceptionInterface ? $e->getStatusCode() : 500;
// allow 500 errors to be thrown
if ($this->debug && $statusCode >= 500) {
return;
}
$this->logException($e);
if ($e instanceof ApiProblemException) {
$apiProblem = $e->getApiProblem();
} else {
$apiProblem = new ApiProblem(
$statusCode
);
/*
* If it's an HttpException message (e.g. for 404, 403),
* we'll say as a rule that the exception message is safe
* for the client. Otherwise, it could be some sensitive
* low-level exception, which should *not* be exposed
*/
if ($e instanceof HttpExceptionInterface) {
$apiProblem->set('detail', $e->getMessage());
}
}
$response = $this->responseFactory->createResponse($apiProblem);
$event->setResponse($response);
}
public static function getSubscribedEvents()
{
return array(
KernelEvents::EXCEPTION => 'onKernelException'
);
}
/**
* Adapted from the core Symfony exception handling in ExceptionListener
*
* @param \Exception $exception
*/
private function logException(\Exception $exception)
{
$message = sprintf('Uncaught PHP Exception %s: "%s" at %s line %s', get_class($exception), $exception->getMessage(), $exception->getFile(), $exception->getLine());
$isCritical = !$exception instanceof HttpExceptionInterface || $exception->getStatusCode() >= 500;
$context = array('exception' => $exception);
if ($isCritical) {
$this->logger->critical($message, $context);
} else {
$this->logger->error($message, $context);
}
}
}