0
은 내가 TourId = 4 청구서와 같은 하나의 행 결과를 얻을 수 실 거예요,하지만 것입니다 행 수는 TourId와가 제공 = 4함수를 호출하여 한 행 결과를 얻으면 행 수가 늘어납니다. 이유는 무엇입니까? 여기에서
--Functions
--(1)Tour Bill
-- when enter a TourID it will genarate Tour Cost
--Multi statement table valued functions
CREATE FUNCTION dbo.Tour_Bill(@TourID int)
RETURNS @Bill TABLE
( TourID int,
ItineraryID int,
StartDate date,
EndDate date,
Duration int,
Distance float,
CustomerId varchar(30)
Name varchar(180) NOT NULL,
ContractNo varchar(12) NOT NULL,
GuideID int,
PaymentForGuide money,
SpecielActivityCost money,
VisitingPlaceTicketCost money,
NumberOfPeople int,
CostForMeal money,
Accomadation varchar(100),
TotalAccommodationCost money,
TourPackegeCost money,
TotalSpecielActivityCost money,
TotalVisitingPlaceTicketCost money,
GRAND_COST money
)
AS
BEGIN
INSERT INTO @Bill
SELECT Tour.TourId,
Itinerary.ItineraryId,
StartDate,
EndDate,
DATEDIFF(day,StartDate,EndDate) AS Duration,
EstTravelDist,
CustomerId,
FirstName+' '+LastName AS FullName,
ContactNo,
Guide.IdNo,
CAST(500 * DATEDIFF(day,StartDate,EndDate) AS money) AS PaymentForGuide,
SpecialActivity.Cost AS SpecialActivityCost,
VisitingPlaces.Cost AS VisitingPlacesCost,
NumberOfPeople,
CAST(UnitPrice * DATEDIFF(day,StartDate,EndDate) * NumberOfPeople AS money) AS CostForMeal,
Location AS Accomadation,
CAST(UnitPrice * DATEDIFF(day,StartDate,EndDate) AS money) AS TotalAccommodationCost,
CAST(EstTravelDist * 40 AS money) AS TourPackegeCost,
SpecialActivity.Cost * NumberOfPeople AS TotalSpecielActivityCost,
VisitingPlaces.Cost * NumberOfPeople AS TotalVisitingPlaceTicketCost,
CAST(EstTravelDist * 40 + SpecialActivity.Cost * NumberOfPeople + VisitingPlaces.Cost * NumberOfPeople + 500 * DATEDIFF(day,StartDate,EndDate)
+ UnitPrice * DATEDIFF(day,StartDate,EndDate) + UnitPrice * DATEDIFF(day,StartDate,EndDate) * NumberOfPeople AS money) AS GRAND_COST
FROM (((((((((Itinerary
INNER JOIN SpecialActivity ON
Itinerary.ItineraryId = SpecialActivity.ItineraryId)
INNER JOIN VisitingPlaces ON
VisitingPlaces.ItineraryId = Itinerary.ItineraryId)
INNER JOIN Tour ON
Tour.TourId = Itinerary.TourId)
INNER JOIN Guide ON
Guide.TourId = Tour.TourId)
INNER JOIN Vehicle ON
Vehicle.TourId = Tour.TourId)
INNER JOIN Accommodation ON
Accommodation.TourId = Tour.TourId)
INNER JOIN Participant ON
Participant.TourId = Tour.TourId)
INNER JOIN Person ON
Person.IdNo = Guide.IdNo)
INNER JOIN Contract ON
Itinerary.ItineraryId = Contract.ItineraryId)
WHERE Tour.TourId = 4
RETURN;
END
--How to Call the Function
SELECT * FROM dbo.Tour_Bill(101)
---These are the tables
create table Itinerary(
ItineraryId int primary key identity,
Description varchar(50)NOT NULL,
TourId int,
CONSTRAINT FK_Tour3 FOREIGN KEY (TourId)
REFERENCES Tour(TourId)
);
--ALTER TABLE ADD COLUMN Distance
ALTER TABLE Itinerary
ADD EstTravelDist float NOT NULL
create table SpecialActivity(
Activity varchar(100),
ItineraryId int NOT NULL,
Dates date ,
PRIMARY KEY(Activity,ItineraryId,Dates),
CONSTRAINT FK_Dates3 FOREIGN KEY (Dates,ItineraryId)
REFERENCES Dates(Dates,ItineraryId),
);
---ADD COLUMN Cost
ALTER TABLE SpecialActivity
ADD Cost money NOT NULL
create table VisitingPlaces(
Place varchar(100),
ItineraryId int,
Dates date ,
PRIMARY KEY(Place,ItineraryId,Dates),
CONSTRAINT FK_Dates5 FOREIGN KEY (Dates,ItineraryId)
REFERENCES Dates(Dates,ItineraryId),
);
---ADD COLUMN Cost
ALTER TABLE VisitingPlaces
ADD Cost money NOT NULL
create table Person(
IdNo varchar(30) primary key,
FirstName varchar(50) NOT NULL ,
LastName varchar (100) NOT NULL,
Gender char(1) NOT NULL,
Nationality varchar (50) NOT NULL,
Email varchar(100) UNIQUE,
Fax varchar(12) ,
PostBox varchar (6) NOT NULL,
Street varchar (60) NOT NULL,
City varchar (60) NOT NULL,
Province varchar (60) NOT NULL,
Country varchar(100) NOT NULL
);
create table Tour(
TourId int PRIMARY KEY IDENTITY,
ResavationDate date NOT NULL,
StartDate date NOT NULL,
EndDate date NOT NULL,
NumberOfPeople int NOT NULL,
TourStatus varchar(20) NOT NULL,
CustomerId varchar(30),
CONSTRAINT FK_Person3 Foreign key (CustomerId)
REFERENCES Person(IdNo)
);
create table Guide(
IdNo VARCHAR(30) PRIMARY KEY ,
GovermentRegistrationNo varchar(10) NOT NULL UNIQUE,
YearsOfExperence int NOT NULL,
TourId int,
CONSTRAINT FK_Tour2 FOREIGN KEY (TourId)
REFERENCES Tour(TourId),
CONSTRAINT FK_Person4 FOREIGN KEY (IdNo)
REFERENCES Guide(IdNo)
);
create table Participant(
ParticipantId varchar(30) primary key,
Name varchar(50) NOT NULL,
ContactNo varchar(30) NOT NULL,
PickupLocation varchar(50) NOT NULL,
DropLocation varchar(50) NOT NULL,
TourId int
CONSTRAINT FK_Tour FOREIGN KEY (TourId) REFERENCES Tour(TourId)
);
create table Accommodation(
ContractNo int primary key ,
Location varchar (50) NOT NULL,
Class varchar(10),
RentedRoomFacilitiesDescription varchar(1000),
PvtRoomFacilitiesDescription varchar(1000),
T1 bit,
T2 bit,
T3 bit,
Dates date,
ItineraryId int,
TourId int,
CONSTRAINT Fk_Dates FOREIGN KEY (Dates,ItineraryId)
REFERENCES Dates(Dates,ItineraryId),
CONSTRAINT FK_Tour4 FOREIGN KEY (TourId)
REFERENCES Tour(TourId),
);
create table Contract(
ContractNo int primary key IDENTITY,
PricingCriteria varchar(100),
UnitPrice money,
MiniPeople int,
MaxPeople int,
ContractType varchar(100),
FinancialPenalty money,
ItineraryId int NOT NULL,
SupplierId int,
CONSTRAINT FK_Itinerary2 FOREIGN KEY (ItineraryId)
REFERENCES Itinerary(ItineraryId),
CONSTRAINT FK_SupplierRegNo FOREIGN KEY (SupplierId) REFERENCES Supplier(SupplierRegNo)
);
여행 ID가 동일한 행이 여러 개있는 경우 원하는 항목은 무엇입니까? 그 여행을위한 몇 가지 필드의 합계. 아님, 아니면? 귀하의 요구 사항이 무엇인지, 그리고 바람직하게는 귀하가 원하는 결과물을 제시하십시오. 동일한 ID를 가진 여러 행이있는 경우 한 행을 가져 오려면 일종의 집계 쿼리를 만들거나 where 절에 추가 제한을 만들어 한 행만 반환 될 수 있도록해야합니다. – ADyson
동일한 ID를 가진 행이 여러 개 없으며 각 Tour @ADyson의 총 비용을 얻지 않을 것입니다. – rajitha
위에서 "TourId = 4 인 행 수가 있습니다."라고 말했습니다. 그러므로 내 의견. – ADyson