-1
올바른 결과가 출력되지 않습니다. 입력에 추가 비용을 곱하는 대신 입력 내용을 그대로 표시합니다. 사람들의 수에 선택에 따른 추가 비용을 곱해야합니다.올바른 곱셈 출력을 얻지 못하는 이유는 무엇입니까?
#!/bin/bash
read -p "Number of Adult Tickets:(0 for none) " integer1
read -p "Number of Junior Tickets:(0 for none) " integer2
echo ""
echo "$integer1 Adults"
echo "$integer2 Juniors"
echo ""
num1=$50
num2=$20
num3=$5
echo "Season Pass Add-On:"
echo "1)Add Seasonal Parking"
echo "2)Add Season Pass For Theme Park"
echo "7)Just Buy Tickets For Today"
echo "8)I wanna exit."
echo ""
read -p "What would the guest like to do? " guest
echo ""
case $guest in
1)
echo "Add Seasonal Parking"
echo ""
echo "Add an additional $num1 for every adult pass"
echo ""
echo "For Adult Tickets "$((integer1 + num1))""
echo "For Junior Tickets "$((integer2 + num1))""
;;
2)
echo "Add Season Pass For Theme Park"
echo ""
echo "Add an additional $num2 for every adult pass"
echo "Add an additional $num3 for every junior pass"
echo ""
echo "For Junior Tickets "$((integer2 * num2))""
echo "For Adult Tickets "$((integer1 * num3))""
echo "For Junior Tickets "$((integer2 * num2))""
echo "For Adult Tickets "$((integer1 * num3))""
;;
3)
echo "Just buy tickets for today"
exit 0
;;
4)
echo "invalid entry. You are exiting"
exit 1
;;
esac
exit 0
고맙습니다. – pinook