SQL 2000 INCORECT 근처의 구문이 코드 사용하고

Question

함께 :

WITH cte AS(SELECT panelname FROM inventorypanelcaptions UNION ALL SELECT CAST(0 AS VARCHAR(50)) FROM INVENTORYPANELCAPTIONS) SELECT CASE WHEN cast(min(right(panelname, 2) + 1) as varchar(50)) < 10 THEN 'o0' ELSE 'o' END + cast(min(right(panelname, 2) + 1) as varchar(50)) FROM cte WHERE NOT EXISTS (SELECT panelname FROM inventorypanelcaptions WHERE right(inventorypanelcaptions.panelname, 2)= right(cte.panelname, 2)+1) ", con); 

을 나는 그것이 SQL 2000에서 작동하려면

Answer 1

'와'잘못된 구문이 가까운지고있어, 당신은에 이동할 수 있습니다 하위 쿼리

SELECT CASE WHEN cast(min(right(panelname, 2) + 1) as varchar(50)) < 10 THEN 'o0' ELSE 'o' END + cast(min(right(panelname, 2) + 1) as varchar(50)) 
    FROM (
     SELECT panelname FROM inventorypanelcaptions UNION ALL SELECT CAST(0 AS VARCHAR(50)) 
     FROM INVENTORYPANELCAPTIONS 
    ) cte 
    WHERE NOT EXISTS ( SELECT panelname 
         FROM inventorypanelcaptions 
         WHERE right(inventorypanelcaptions.panelname, 2)= right(cte.panelname, 2)+1 
        ) ", con);