주어진 XML이 있고 새 XML로 변환하고 상태 및 orderId를 기반으로 노드를 집계하고 싶습니다.새로운 부모 아래 conditon을 기반으로하는 집계 노드
<?xml version="1.0" encoding="utf-8"?>
<OrderStatusUpdate>
<OrderStatusEvents>
<OrderStatusEvent>
<StoreCode>store1</StoreCode>
<OrderId>Order1</OrderId>
<ItemId>Item1</ItemId>
<OrderStatusDetails>
<OrderStatusDetail>
<OrderStatusEventTimeStamp>2017-03-19 03:37:05</OrderStatusEventTimeStamp>
<StatusName>Cancelled</StatusName>
</OrderStatusDetail>
</OrderStatusDetails>
</OrderStatusEvent>
<OrderStatusEvent>
<StoreCode>Store1</StoreCode>
<OrderId>Order1</OrderId>
<ItemId>Item2</ItemId>
<OrderStatusDetails>
<OrderStatusDetail>
<OrderStatusEventTimeStamp>2017-03-19 03:48:35</OrderStatusEventTimeStamp>
<StatusName>Cancelled</StatusName>
</OrderStatusDetail>
</OrderStatusDetails>
</OrderStatusEvent>
<OrderStatusEvent>
<StoreCode>Store1</StoreCode>
<OrderId>Order1</OrderId>
<ItemId>Item3</ItemId>
<OrderStatusDetails>
<OrderStatusDetail>
<OrderStatusEventTimeStamp>2017-03-19 03:48:35</OrderStatusEventTimeStamp>
<StatusName>Shipped</StatusName>
</OrderStatusDetail>
</OrderStatusDetails>
</OrderStatusEvent>
<OrderStatusEvent>
<StoreCode>Store1</StoreCode>
<OrderId>Order2</OrderId>
<ItemId>Item1</ItemId>
<OrderStatusDetails>
<OrderStatusDetail>
<OrderStatusEventTimeStamp>2017-03-19 03:48:35</OrderStatusEventTimeStamp>
<StatusName>Cancelled</StatusName>
</OrderStatusDetail>
</OrderStatusDetails>
</OrderStatusEvent>
</OrderStatusEvents>
</OrderStatusUpdate>
그리고 이렇게 출력하고 싶습니다. 여기서는 상태 및 주문 ID를 기반으로 요소를 그룹화합니다.
<Orders>
<group name="CANCELLED">
<STATUS ID="CANCELLED" DESCRIPTION="Goods Cancelled">
<ORDER ID="Order1">
<ORDER_ITEM item="item1" />
<ORDER_ITEM item="item2" />
</ORDER>
</STATUS>
<STATUS ID="CANCELLED" DESCRIPTION="Goods Cancelled">
<ORDER ID="Order2">
<ORDER_ITEM item="item1" />
</ORDER>
</STATUS>
</group>
<group name="SHIPPED">
<STATUS ID="SHIPPED" DESCRIPTION="Goods SHIPPED">
<ORDER ID="Order1">
<ORDER_ITEM item="item3" />
</ORDER>
</STATUS>
<group>
</Orders>
다음 xslt를 사용 중입니다. 정상적으로 작동합니다. 이를 개선 할 방법이 있습니까?
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes" />
<xsl:template match="OrderStatusUpdate/OrderStatusEvents">
<Orders>
<xsl:for-each-group select="OrderStatusEvent" group-by="OrderStatusDetails/OrderStatusDetail/StatusName">
<xsl:variable name="group-name" select="current-grouping-key()" />
<group name="{current-grouping-key()}">
<xsl:for-each-group select="current-group()" group-by="OrderId">
<xsl:variable name="order-id" select="current-grouping-key()" />
<xsl:element name="STATUS">
<xsl:attribute name="ID"><xsl:value-of select="$group-name" /></xsl:attribute>
<xsl:attribute name="DESCRIPTION">Goods <xsl:value-of select="$group-name" /></xsl:attribute>
<xsl:element name="ORDER">
<xsl:attribute name="ID"><xsl:value-of select="$order-id" /></xsl:attribute>
<xsl:for-each select="current-group()">
<xsl:if test="$group-name = 'Shipped'">
<xsl:call-template name="Shipped">
<xsl:with-param name="nodes">
<xsl:copy-of select="." />
</xsl:with-param>
</xsl:call-template>
</xsl:if>
<xsl:if test="$group-name = 'Cancelled'">
<xsl:call-template name="Cancelled">
<xsl:with-param name="nodes">
<xsl:copy-of select="." />
</xsl:with-param>
</xsl:call-template>
</xsl:if>
</xsl:for-each>
</xsl:element>
</xsl:element>
</xsl:for-each-group>
</group>
</xsl:for-each-group>
</Orders>
</xsl:template>
<xsl:template name="Shipped">
<xsl:param name="nodes">
</xsl:param>
<xsl:element name="ORDER_ITEM">
<xsl:attribute name="ID"><xsl:value-of select="$nodes/OrderStatusEvent/ItemId" /></xsl:attribute>
</xsl:element>
</xsl:template>
<xsl:template name="Cancelled">
<xsl:param name="nodes"></xsl:param>
<xsl:element name="ORDER_ITEM">
<xsl:attribute name="ID"><xsl:value-of select="$nodes/OrderStatusEvent/ItemId" /></xsl:attribute>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
음을 사용하기에 충분 https://www.w3.org/TR/xslt20/#grouping-examples. –
그룹을 만들 수 있지만 상위 요소를 추가 할 수 없습니다. 나는 for-each-group for status를 시도하고있다. orderId에 대해 다른 for-each-group을 사용하고 있지만 유사한 orderId 항목에 대한 부모 요소를 만들 수 없다. –
중첩 된'xsl : for -each-group'을 사용하면 생성 한 결과와 함께 해결할 수 있다고 확신합니다. –