Postgresql은 열 이름이 아닌 값만 반환하는 함수를 저장합니다.

Question

PostgreSQL에서 새로 도입되었습니다. 방금 복합 유형으로 함수를 만들었습니다.

다음

내 코드입니다 :

create type search_type as (
result_id bigint, 
result_name character varying, 
result_loc character varying, 
result_type character varying, 
result_pic character varying 
); 

    CREATE OR REPLACE FUNCTION search_result("@search_text" character varying) 
    RETURNS SETOF search_type AS 
$BODY$ 
DECLARE r search_type%rowtype; 
BEGIN 
    FOR r IN SELECT "User_id" AS result_id, CONCAT("User_firstname", ' ', "User_lastname") AS result_name, "User_loc" AS result_loc, "User_picurl" AS result_pic, 'user' AS result_type FROM users_list WHERE CONCAT("User_firstname", ' ', "User_lastname") LIKE CONCAT("@search_text", '%') LOOP 
     RETURN NEXT r; 
    END LOOP; 
    FOR r IN SELECT "Community_id" AS result_id, "Community_name" AS result_name, "Community_location" AS result_loc, "Community_img_url" AS result_pic, 'community' AS result_type FROM community_list WHERE "Community_name" LIKE CONCAT("@search_text", '%') AND "Type" = 'Created' LOOP 
     RETURN NEXT r; 
    END LOOP; 
    RETURN; 
END 
$BODY$ 
    LANGUAGE plpgsql 

하지만 아래의 코드처럼 저장 함수를 호출 할 때, 그것은 것입니다에만 열 이름하지 datas.

SELECT search_result('c'); 

어떤 이유가 있을까요?

어떻게 열 이름을 값으로 반환 할 수 있습니까?

위의 내용은 반환 된 recorsd입니다.

result_id result_name result_loc  result_pic result_type 
--------- ----------- ----------  ----------- ---------- 
13   test1  San Francisco    user 
14   test2  San Francisco    user 
15   test3  San Francisco    user 
16   test4  San Francisco    user 
17   test5  San Francisco    user 

어떻게 내가 위의 같은 결과를 얻을 수 있습니다

하지만 난 같은 결과를 얻을 필요가?

UPDATE

새로운 코드 :

CREATE OR REPLACE FUNCTION search_result("@search_text" character varying, "@row_start" integer, "@row_end" integer) 
    RETURNS SETOF search_type AS 
$BODY$ 
DECLARE r search_type%rowtype; 
BEGIN 
    FOR r IN SELECT "User_id" AS result_id, CONCAT("User_firstname", ' ', "User_lastname") AS result_name, "User_loc" AS result_loc, "User_picurl" AS result_pic, 'user' AS result_type FROM users_list WHERE CONCAT("User_firstname", ' ', "User_lastname") LIKE CONCAT("@search_text", '%') ORDER BY CONCAT("User_firstname", ' ', "User_lastname") ASC LIMIT "@row_end" OFFSET "@row_start" LOOP 
     RETURN NEXT r; 
    END LOOP; 
    FOR r IN SELECT "Community_id" AS result_id, "Community_name" AS result_name, "Community_location" AS result_loc, "Community_img_url" AS result_pic, 'community' AS result_type FROM community_list WHERE "Community_name" LIKE CONCAT("@search_text", '%') AND "Type" = 'Created' ORDER BY "Community_name" ASC LIMIT "@row_end" OFFSET "@row_start" LOOP 
     RETURN NEXT r; 
    END LOOP; 
    RETURN; 
END 
$BODY$ 
    LANGUAGE plpgsql 

그럼 내가 같은 절차라고 :

SELECT * FROM search_result('t',3,0) 

을하지만, 더 값이 반환되지 않습니다.

Answer 1

당신이 필요합니다

SELECT * FROM search_result('c'); 

아니라 :

SELECT search_result('c'); 

당신이 테이블 결과를 원하는 경우. SELECT에서 호출 된 집합 반환 함수는 복합 튜플을 반환합니다.