이 두 가지 복잡한 쿼리를 어떻게 참여시킬 수 있습니까?

Question

두 가지 쿼리가 있습니다.이 두 쿼리는 매우 잘 맞았습니다. 따라서이 두 메서드를 결합하는 방법을 찾지 못했습니다.

SELECT DISTINCT notifications.`receiver` AS notAnyFewID 
FROM notifications 
JOIN 
(SELECT notifications.`ref` AS notRef, notifications.`receiver` AS recI 
    FROM notifications 
    WHERE notifications.`ref`='tooFewLandings') AS c 
ON notifications.`receiver`=c.recI 
WHERE notifications.`receiver`!=c.recI 

는 Q2 :

SELECT DISTINCT R2PProfiles.id AS r2pID, R2PProfiles.`facebookID` AS FBID 
FROM R2PProfiles 
LEFT JOIN 
     (SELECT COUNT(*) AS Landings, R2PProfiles.facebookID, R2PProfiles.id 
      FROM pageTrack   
      JOIN (R2PProfiles) 
     ON (pageTrack.inputRefNum = R2PProfiles.id) 
WHERE pageTrack.ref='getProfile-Land' AND R2PProfiles.published=2 AND R2PProfiles.`createTime`< NOW()- INTERVAL 24 HOUR GROUP BY R2PProfiles.id) AS h 
USING (id) WHERE (Landings < 20) 

나는 것 그들을 결합하려고 항상 엉망하는

나는 두 쿼리의 Q1.notAnyFewID = Q2.FBID이

가 이

Q1 때 결과 세트를 찾으려면 가입 또는 하위 선택 또는 "사용"또는 어디서 어떻게 새 정보를 얻을 수 있는지 알려줍니다.

쿼리 중 하나를 다른 쿼리의 결과와 비교하는 가장 좋은 방법은 무엇입니까? 다른 프로그래밍 언어에서 그렇게 할 이유

Answer 1

은 그냥 JOIN

SELECT notAnyFewID, r2pID 
FROM (SELECT DISTINCT notifications.`receiver` AS notAnyFewID 
     FROM notifications 
     JOIN 
     (SELECT notifications.`ref` AS notRef, notifications.`receiver` AS recI 
      FROM notifications 
      WHERE notifications.`ref`='tooFewLandings') AS c 
     ON notifications.`receiver`=c.recI 
     WHERE notifications.`receiver`!=c.recI) AS q1 
JOIN (SELECT DISTINCT R2PProfiles.id AS r2pID, R2PProfiles.`facebookID` AS FBID 
     FROM R2PProfiles 
     LEFT JOIN 
       (SELECT COUNT(*) AS Landings, R2PProfiles.facebookID, R2PProfiles.id 
        FROM pageTrack   
        JOIN (R2PProfiles) 
       ON (pageTrack.inputRefNum = R2PProfiles.id) 
     WHERE pageTrack.ref='getProfile-Land' AND R2PProfiles.published=2 AND R2PProfiles.`createTime`< NOW()- INTERVAL 24 HOUR GROUP BY R2PProfiles.id) AS h 
     USING (id) WHERE (Landings < 20)) AS q2 
ON q1.notAnyFewID = q2.FBID