MATLAB - 속성

Question

나는 matlab에 간단한 암호 프로그램을 만들었습니다. 아시다시피 일반적인 암호 프로그램은 암호를 3 회 잘못 입력하면 프로그램이 잠긴 것입니다. 오류. 속성을 추가하려면 어떻게해야합니까?

while (x ~= 1111) 
    if (x == password) 
     uiwait(msgbox('Welcome!')); 
     break; 
    else 
     uiwait(errordlg('Try Again!!')); 

     X = inputdlg('Please enter your password'); 
     x = str2double (X{1,1}); 
    end 
end 
uiwait(msgbox('Welcome!')); 
end 

Answer 1

당신은 루프 내에서 반복 카운터 넣을 수 :

locked_flag = false 
counter = 0 
while (x ~= 1111) 
    if (x == password) 
     uiwait(msgbox('Welcome!')); 
     break; 
    else 
     uiwait(errordlg('Try Again!!')); 
     counter = counter + 1 
     if (counter == 3) 
      locked_flag = true; 
      %show 'locked' dialog of some kind here 
      break; 
     end 

     X = inputdlg('Please enter your password'); 
     x = str2double (X{1,1}); 
    end 
end 
%can now check if locked_flag true to start unlock logic or other... 

편집 : 예 난 단지 코드의 조각을 게시 것을, 당신은, 위의 논리가 필요합니다 같은, 그 경우 죄송는 분명하지 않다 :

X = inputdlg ('Please enter your password'); 
x = str2double (X {1,1}); 
password = 1111; %whatever 
if (x == password) 
    uiwait(msgbox('Welcome!')); 
else 
    locked_flag = false 
    counter = 1 
    while (x ~= 1111) 
     if (x == password) 
      uiwait(msgbox('Welcome!')); 
      break; 
     else 
      uiwait(errordlg('Try Again!!')); 
      counter = counter + 1 
      if (counter == 3) 
       locked_flag = true; 
       %show 'locked' dialog of some kind here 
       break; 
      end 

      X = inputdlg('Please enter your password'); 
      x = str2double (X{1,1}); 
     end 
    end 
end 
%can now check if locked_flag true to start unlock logic or other... 

Answer 2

wrong = 0; 
lock = false; 

% Keeping a char type allows you to use different 
% types of passwords (i.e. alphanumeric). 
password = '1111'; 

% Infinite loop, which allows you to implement full 
% control over the iterations. 
while (true)  
    pass = inputdlg('Please enter your password:'); 

    % If the user pushes the Cancel button, he is not inserting a 
    % wrong password, so no action should be taken towards locking. 
    % If he pushes the Ok button with empty textbox, {''} is 
    % returned, which could be wrong. 
    if (isempty(pass)) 
     continue; 
    end 

    if (strcmp(pass,password)) 
     uiwait(msgbox('Welcome!')); 
     break; 
    else 
     uiwait(errordlg('Try again!')); 
     wrong = wrong + 1; 

     if (wrong == 3) 
      lock = true; 
      break; 
     end 
    end 
end 

if (lock) 
    uiwait(errordlg('Application locked!')); 
    return; 
end 

% Your logic starts here...