TSQL Row_Number

Question

이 질문은 이전에 유사하게 다루어졌지만 지금은 어려움을 겪고 있습니다.

내가 고객의 구매 패턴을 기반으로 상위 N 판매를 찾을 필요가

..

이상적이 올해의 달 기간으로 고객이 상위 N 수 있어야하지만 지금 난 그냥 전체에 걸쳐 상위 N 찾고 있어요 DB.

-- QUERY TO SHOW TOP 2 CUSTOMER INVOICES BY CUSTOMER BY MONTH 

SELECT 
    bill_to_code, 
    INVOICE_NUMBER, 
    SUM(INVOICE_AMOUNT_CORP) AS 'SALES', 
    ROW_NUMBER() OVER (PARTITION BY bill_to_code ORDER BY SUM(INVOICE_AMOUNT_CORP) DESC) AS 'Row' 
FROM 
    FACT_OM_INVOICE 
    JOIN dim_customer_bill_to ON FACT_OM_INVOICE.dim_customer_bill_to_key = dim_customer_bill_to.dim_customer_bill_to_key 
--WHERE 
-- 'ROW' < 2 
GROUP BY 
    invoice_number, 
    Dim_customer_bill_to.bill_to_code 

내가 행 = < N.

도와주세요

에 제한을 주어진 솔루션을 이해할 수 없다 :

내 쿼리는 것 같습니다.

Answer 1

시도해보십시오.

-- QUERY TO SHOW TOP 2 CUSTOMER INVOICES BY CUSTOMER BY MONTH 
;WITH Top2Customers 
AS 
(
SELECT 
    bill_to_code, 
    INVOICE_NUMBER, 
    SUM(INVOICE_AMOUNT_CORP) AS 'SALES', 
    ROW_NUMBER() OVER (PARTITION BY bill_to_code ORDER BY SUM(INVOICE_AMOUNT_CORP) DESC) 
    AS 'RowNumber' 
FROM 
    FACT_OM_INVOICE 
    JOIN dim_customer_bill_to ON FACT_OM_INVOICE.dim_customer_bill_to_key = dim_customer_bill_to.dim_customer_bill_to_key 
GROUP BY 
    invoice_number, 
    Dim_customer_bill_to.bill_to_code 
) 
SELECT * FROM Top2Customers WHERE RowNumber < 3 

Answer 2

당신은 ROW_NUMBER에 의해 생성 된 값()

select * from (
SELECT 
    bill_to_code, 
    INVOICE_NUMBER, 
    SUM(INVOICE_AMOUNT_CORP) AS SALES, 
    ROW_NUMBER() OVER (PARTITION BY bill_to_code ORDER BY SUM(INVOICE_AMOUNT_CORP) DESC) AS RowNo 
FROM 
    FACT_OM_INVOICE 
    JOIN dim_customer_bill_to ON FACT_OM_INVOICE.dim_customer_bill_to_key = dim_customer_bill_to.dim_customer_bill_to_key 
--WHERE 
-- 'ROW' < 2 
GROUP BY 
    invoice_number, 
    Dim_customer_bill_to.bill_to_code 
) base where RowNo < 2