TypeError : __init __()는 정확히 2 개의 인수 (주어진 경우 1 개)를가집니다. Flask

Question

이 상황에서는 default = 'value'를 제공해야한다는 것을 알고 있습니다. StackOverFlow를 통한 솔루션과 의논했지만이 오류를 없앨 수는 없습니다. 기본값이 있거나 없으면 관리자 양식에서 저장하는 동안이 오류가 발생합니다. 초기화 기능에서 Packeges 모듈에 오류가 있습니다. 제발 조언.

class Packeges(db.Model): 
    __tablename__ = 'packages' 
    id = db.Column(db.Integer, primary_key=True) 
    package_name = db.Column(db.String(30), default='Add Package Here') 
    def __init__(self, package_name): 
     self.package_name = package_name 


admin.add_view(ModelView(Packeges, db.session)) 

class UserSubscription(db.Model): 
    __tablename__ = 'user_subscription' 
    id = db.Column(db.Integer, primary_key=True) 
    user_profile = db.Column(db.String(80), unique=True) 
    package_name = db.Column(db.Integer, db.ForeignKey(Packeges.id)) 
    packages = db.relationship(Packeges, backref='package') 
    timestamp = db.Column(db.DateTime) 
    expiry = db.Column(db.DateTime) 

    def __init__(self, user_profile, package_name, timestamp, expiry): 
     self.user_profile = user_profile 
     self.package_name = package_name 
     self.timestamp = timestamp 
     self.expiry = expiry 
admin.add_view(ModelView(UserSubscription, db.session)) 

역 추적 : 다음 내 코드입니다

TypeError 
TypeError: __init__() takes exactly 2 arguments (1 given) 

Traceback (most recent call last) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1994, in __call__ 
return self.wsgi_app(environ, start_response) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1985, in wsgi_app 
response = self.handle_exception(e) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1540, in handle_exception 
reraise(exc_type, exc_value, tb) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1982, in wsgi_app 
response = self.full_dispatch_request() 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1614, in full_dispatch_request 
rv = self.handle_user_exception(e) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1517, in handle_user_exception 
reraise(exc_type, exc_value, tb) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1612, in full_dispatch_request 
rv = self.dispatch_request() 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask\app.py", line 1598, in dispatch_request 
return self.view_functions[rule.endpoint](**req.view_args) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask_admin\base.py", line 69, in inner 
return self._run_view(f, *args, **kwargs) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask_admin\base.py", line 368, in _run_view 
return fn(self, *args, **kwargs) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask_admin\model\base.py", line 1920, in create_view 
model = self.create_model(form) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask_admin\contrib\sqla\view.py", line 1028, in create_model 
Open an interactive python shell in this frameif not self.handle_view_exception(ex): 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask_admin\contrib\sqla\view.py", line 1011, in handle_view_exception 
return super(ModelView, self).handle_view_exception(exc) 
File "C:\Users\AliKhan\flask_ecom\env\lib\site-packages\flask_admin\contrib\sqla\view.py", line 1022, in create_model 
model = self.model() 

Answer 1

다음과 같이하십시오 : 우리는 상황을 볼 수 있도록

이

def __init__(self, **kwargs): 
     for key, value in kwargs.items(): 
      setattr(self, key, value)