mySQL의 다른 테이블에서 select 결과를 가진 테이블의 필드를 업데이트하십시오.

Question

후속 질문이 있습니다. sum of counts of different columns of same table 다른 테이블 (B)의 필드 (Z)를 업데이트하고 싶습니다. 결과 선택 쿼리 (A.COUNT_TOTAL) : 나는 문 다음 시도

SELECT A.ID, SUM(A.COUNTS) AS COUNT_TOTAL 
FROM 
(
SELECT X AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY X 
UNION ALL 
SELECT Y AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY Y 
) A 
GROUP BY A.ID 
ORDER BY A.ID;` 

, (그러나 막연한 오류 메시지가 얻을) :

UPDATE B 
    INNER JOIN (
    SELECT A.ID, SUM(A.COUNTS) AS COUNT_TOTAL 
    FROM 
    (
    SELECT X AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY X 
    UNION ALL 
    SELECT Y AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY Y 
    ) A 
    GROUP BY A.ID) as A on B.ID = A.ID 
    SET B.Z = A.COUNT_TOTAL 

Answer 1

을 당신은 ambiguos (및 별명 A와 잘못된 참조가 있습니다. 다른 별칭에 대해 동일한 이름을 두 번 사용하고 있습니다.) 다른 하위 쿼리에 다른 별칭 사용 (예 :

)

UPDATE B 
    INNER JOIN (
    SELECT A.ID, SUM(A.COUNTS) AS COUNT_TOTAL 
    FROM 
    (
    SELECT X AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY X 
    UNION ALL 
    SELECT Y AS ID, COUNT(*) AS COUNTS FROM TABLE1 GROUP BY Y 
) A 
    GROUP BY A.ID) T on B.ID = T.ID 
    SET B.Z = T.COUNT_TOTAL