json to Rails의 신속한 게시물

Question

나는 신속하게 json 값을 Rails에 게시 할 수 없습니다.

내 레일 코드는

def create 

    @movie = Movie.new 
    @movie.caption = movie_params["caption"] 
    @movie.language = movie_params["language"] 
    @movie.movie_file = movie_params["movie_file"] 
    @movie.save 
end 


def movie_params 
    params.require(:movie).permit(:caption, :language, :movie_file) 
end 

컬이 잘 작동합니다.

curl -v -H 'Content-Type: application/json' -H 'Accept: application/json' -X POST -d '{"movie":{"caption":"hoge","language":"TH","movie_file":"2016-10-16T14-30-30"}}' http://localhost:3000/movies.json 

그러나 어떻게 신속하게 json을 게시 할 수 있습니까?
엑스 코드 환경입니다
AFNetworking 3.0
SwiftyJSON 2.3.2 내 빠른 코드 내가이를 게시 할 때, 나는 레일 출력에 오류가 발생했습니다

let dict: [String: AnyObject] = [ 
     "movie": [ 
      "caption": "hoge", 
      "language":"", 
      "movie_file":"" 
     ] 
    ] 

var json: String = "" 
do { 
// Dict -> JSON 
     let jsonData = try NSJSONSerialization.dataWithJSONObject(dict, options: []) //(*)options?? 

     json = NSString(data: jsonData, encoding: NSUTF8StringEncoding)! as String 
    } catch { 
     print("Error!: \(error)") 
    } 

    let strData = json.dataUsingEncoding(NSUTF8StringEncoding) 


    let manager: AFHTTPSessionManager = AFHTTPSessionManager() 
    manager.requestSerializer.setValue("application/json", forHTTPHeaderField: "Content-Type") 
    manager.responseSerializer.acceptableContentTypes = NSSet(object: "application/json") as? Set<String> 

    let server_request = String(format: "%@/%@", self.server_url, request) 

    let escapedRequest = server_request.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet()) 


    // here "jsonData" is the dictionary encoded in JSON data 

    manager.POST(escapedRequest!, parameters: strData, progress: nil, success: { (operation, dataFromNetworking) -> Void in 

     let jsonObj = JSON(dataFromNetworking!) 
     callback(jsonObj) 

     }, failure:{ (operation, error) -> Void in 

    }) 

입니다

Started POST "/movies.json" for 127.0.0.1 at 2016-10-20 10:40:52 +0700 
Error occurred while parsing request parameters. 
Contents:  =%3C7b226d6f%2076696522%203a7b226c%20616e6775%2061676522%203a22222c%2022636170%2074696f6e%20223a2268%206f676522%202c226d6f%207669655f%2066696c65%20223a2222%207d7d%3E 

ActionDispatch::ParamsParser::ParseError (822: unexpected token at '=%3C7b226d6f%2076696522%203a7b226c%20616e6775%2061676522%203a22222c%2022636170%2074696f6e%20223a2268%206f676522%202c226d6f%207669655f%2066696c65%20223a2222%207d7d%3E'): 
actionpack (4.2.5) lib/action_dispatch/middleware/params_parser.rb:53:in `rescue in parse_formatted_parameters' 
actionpack (4.2.5) lib/action_dispatch/middleware/params_parser.rb:32:in `parse_formatted_parameters' 

너를 도와 주셔서 정말 고맙습니다. 나는 온종일 고생하고있다. 미리 감사드립니다.

톰

Answer 1

이 시도

do { 

    let jsonData = try NSJSONSerialization.dataWithJSONObject(dict, options: .PrettyPrinted) 

    // create post request 
    let url = NSURL(string: "https://...your_host.com/movies.json")! 
    let request = NSMutableURLRequest(URL: url) 
    request.HTTPMethod = "POST" 

    // insert json data to the request 
    request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type") 
    request.HTTPBody = jsonData 


    let task = NSURLSession.sharedSession().dataTaskWithRequest(request){ data, response, error in 
     if error != nil{ 
      print("Error -> \(error)") 
      return 
     } 

     do { 
      let result = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? [String:AnyObject] 

      print("Result -> \(result)") 

     } catch { 
      print("Error -> \(error)") 
     } 
    } 

    task.resume() 
    return task 



} catch { 
    print(error) 
} 

참조 : How to make HTTP Post request with JSON body in Swift