2016-11-05 14 views
1

jsp 페이지에 CSS 파일을 포함시키고 싶습니다. 나는 stackoverflow, 구글에서 모든 솔루션을 시도 ...하지만 여전히 아무것도, 그것은 CSS 코드를 인식하지 못합니다.스프링 mvc 리소스 파일은 jsp 페이지에 포함될 수 없습니다 (Tomcat v9.0, Spring Tool Suite, Maven)

I이 3 개 솔루션 시도 :

<link href="<c:url value="/resources/css/main.css" />" rel="stylesheet"> 
<spring:url value="/resources/css/main.css" var="mainCss" /> 
<link type="text/css" href="${pageContext.request.contextPath}/css/main.css" rel="stylesheet" /> 

서블릿의 context.xml

<?xml version="1.0" encoding="UTF-8"?> 
<beans:beans xmlns="http://www.springframework.org/schema/mvc" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:beans="http://www.springframework.org/schema/beans" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xsi:schemaLocation="http://www.springframework.org/schema/mvc 
    http://www.springframework.org/schema/mvc/spring-mvc.xsd 
     http://www.springframework.org/schema/beans 
     http://www.springframework.org/schema/beans/spring-beans.xsd 
     http://www.springframework.org/schema/context 
     http://www.springframework.org/schema/context/spring-context.xsd 
     http://www.springframework.org/schema/mvc 
     http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd"> 

    <context:component-scan base-package="com.projekt.springmvc" /> 

    <annotation-driven /> 

    <resources mapping="/resources/**" location="/resources/css/" /> 

    <default-servlet-handler /> 

    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
     <beans:property name="prefix" value="/WEB-INF/views/" /> 
     <beans:property name="suffix" value=".jsp" /> 
    </beans:bean> 
</beans:beans> 

web.xml의

<?xml version="1.0" encoding="UTF-8"?> 
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> 

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters --> 
    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/spring/root-context.xml</param-value> 
    </context-param> 

    <!-- Creates the Spring Container shared by all Servlets and Filters --> 
    <listener> 
     <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener> 

    <!-- Processes application requests --> 
    <servlet> 
     <servlet-name>appServlet</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <init-param> 
      <param-name>contextConfigLocation</param-name> 
      <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> 
     </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
     <servlet-name>appServlet</servlet-name> 
     <url-pattern>/</url-pattern> 
    </servlet-mapping> 
</web-app> 

home.jsp

봄 도구 스위트로 만든

main.css가

body{ 
    padding-top:70px; 
    font-size:30px; 
    } 

MVC 프로젝트. 이 구성

<link href="<c:url value="/resources/main.css"/>" rel="stylesheet"> 

설명

:

<resources mapping="/resources/**" location="/resources/css/" /> 

을 당신은 /resources/css의 모든 내용을 할당 할 수 있습니다 프로젝트는이 시도 메이븐, JRE_8, 톰캣 V9.0

답변

0

를 사용 봄 매핑은 /resources/입니다. 당신이 진짜 /resources/style에 대한 링크를 시도하면 /resources/style/style에 대한 링크입니다.

최고의 솔루션

변경에 구성 :

<resources mapping="/css/**" location="/resources/css/" /> 

및 사용 :

봄 도구 스위트
<link href="<c:url value="/css/main.css"/>" rel="stylesheet"> 
+0

이클립스 작품,하지만 흥미로운 ... 주셔서 감사합니다 해결책!!! :) – Ivan