나는 3 년 넘게 포인터를 사용하지 않았으며이 주제에 대해 매우 녹슨합니다. 다음 코드를 컴파일 할 때 많은 오류가 발생했습니다.포인터 컴파일러 문제
[email protected]:~/Desktop/stuff$ g++ test.cpp LinearNode.cpp LinkedList.cpp
LinkedList.cpp: In member function ‘void LinkedList::add(int)’:
LinkedList.cpp:26: error: request for member ‘getElement’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp:31: error: request for member ‘getNext’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp:39: error: request for member ‘setPrevious’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp:40: error: cannot convert ‘LinearNode’ to ‘LinearNode*’ in assignment
LinkedList.cpp: In member function ‘int LinkedList::remove(int)’:
LinkedList.cpp:60: error: request for member ‘getElement’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp:62: error: request for member ‘getElement’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp:63: error: request for member ‘getNext’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp:67: error: invalid conversion from ‘LinearNode*’ to ‘int’
LinkedList.cpp:67: error: initializing argument 1 of ‘LinearNode::LinearNode(int)’
LinkedList.cpp:68: error: request for member ‘getNext’ in ‘((LinkedList*)this)->LinkedList::contents’, which is of non-class type ‘LinearNode*’
LinkedList.cpp: In member function ‘void LinkedList::print()’:
LinkedList.cpp:97: error: invalid conversion from ‘LinearNode*’ to ‘int’
LinkedList.cpp:97: error: initializing argument 1 of ‘LinearNode::LinearNode(int)’
링크 List.h :
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include<iostream>
#include"LinearNode.h"
using namespace std;
class LinearNode;
class LinkedList
{
public:
LinkedList();
void add(int element);
int remove (int element);
void print();
private:
int count;
LinearNode* contents;
};//ends the class linked list
#endif
링크 된 목록 :
#include<iostream>
#include"LinearNode.h"
#include"LinkedList.h"
using namespace std;
//linkedlist constructor for an empty linked list
LinkedList::LinkedList()
{
count = 0;
contents = NULL;
}//ends the constructor
//adds an element to the front of the linked list
void LinkedList::add(int element)
{
int found = 0, current = 0;
for (int index = 0; index < count; index++)
{
if (contents.getElement() == element)
found = 1;
else
{
contents = *contents.getNext();
}//ends the else statement
}//ends the while loop
if (found == 0)
{
LinearNode node(element);
node.setNext(contents);
contents.setPrevious(&node);
contents = node;
count++;
//print();
cout << endl;
}//ends the found == 0 if statment
}//ends the add function
//this function removes one element from the linked list.
int LinkedList::remove(int element)
{
int found = 0, result = 0;
LinearNode previous;
LinearNode current;
if (count == 0)
cout << "The list is empty" << endl;
else
{
if (contents.getElement() == element)
{
result = contents.getElement();
contents = *contents.getNext();
}//ends the contents.getElement() == element
else
{
previous = contents;
current = *contents.getNext();
for (int index = 0; ((index < count) && (found == 0)); index++)
if (current.getElement() == element)
found = 1;
else
{
previous = current;
current = *current.getNext();
}//ends the else statement
if (found == 0)
cout << "The element is not in the list" << endl;
else
{
result = current.getElement();
previous.setNext(current.getNext());
}//ends else statement
}//ends the else stamtement
count--;
}//ends the else statement of count == 0
return result;
}//ends the remove function
void LinkedList::print()
{
LinearNode current;
current = contents;
for (int index = 0; index < count; index++)
{
cout << current.getElement() << endl;
current = *current.getNext();
}//ends the for loop
}//ends Print function
LinearNode.h :
#ifndef LINEARNODE_H
#define LINEARNODE_H
#include<iostream>
using namespace std;
class LinearNode
{
public:
//Constructor for the LinearNode class that takes no arguments
LinearNode();
//Constructor for the LinearNode class that takes the element as an argument
LinearNode(int el);
//returns the next node in the set.
LinearNode* getNext();
//returns the previous node in the set
LinearNode* getPrevious();
//sets the next element in the set
void setNext(LinearNode* node);
//sets the previous element in the set
void setPrevious(LinearNode* node);
//sets the element of the node
void setElement(int el);
//gets the element of the node
int getElement();
private:
LinearNode* next;
LinearNode* previous;
int element;
};//ends the LinearNode class
#endif
LinearNode :
,536,913을 다음과 같이 오류가 있습니다#include<iostream>
#include"LinearNode.h"
using namespace std;
//Constructor for LinearNode, sets next and element to initialized states
LinearNode::LinearNode()
{
next = NULL;
element = 0;
}//ends LinearNode default constructor
//Constructor for LinearNode takes an element as argument.
LinearNode::LinearNode(int el)
{
next = NULL;
previous = NULL;
element = el;
}//ends LinearNode constructor
//returns the next element in the structure
LinearNode* LinearNode::getNext()
{
return next;
}//ends getNext function
//returns previous element in structure
LinearNode* LinearNode::getPrevious()
{
return previous;
}//ends getPrevious function
//sets the next variable for the node
void LinearNode::setNext(LinearNode* node)
{
next = node;
}//ends the setNext function
//sets previous for the node
void LinearNode::setPrevious(LinearNode* node)
{
previous = node;
}//ends the setPrevious function
//returns element of the node
int LinearNode::getElement()
{
return element;
}//ends the getelement function
//sets the element of the node
void LinearNode::setElement(int el)
{
element = el;
}//ends the setElement function
, 당신은 http://www.yolinux.com합니다 ([STL 목록]을 사용할 수 있습니다 /TUTORIALS/LinuxTutorialC++STL.html#LIST) 이미 디버깅 된 것을 얻으십시오. STL 목록 템플릿에 대한 자세한 내용은 [cplusplus.com에 자세한 참조 정보가 있습니다.] (http://cplusplus.com/reference/stl/list/)를 참조하십시오. – sarnold
@sarnold 숙제 문제 일 수 있습니다. – mgiuca
@mgiuca, 또는 취업 인터뷰 전에 포인터를 얻으려는 시도 :) 그러나 원래 포스터가 C++을 수행 한 지 오래 되었 더라면 강력한 사전 작성된 놀라운 범위에 익숙하지 않을 수도 있습니다 도구. – sarnold