내 코드 같은
자바 :
@Autowired
private RedisTemplate<String,User> myTemplate;
@Override
public String login(String email, String password) {
User user = this.userRepository.findByEmailAndPassword(email, password);
System.out.println(user);
if (user == null) return null;
String key1 = "lic" + "$" + user.getId() + "$" + user.getRole() + "$" + user.getName() + "$" + user.getEmail();
ValueOperations<String, User> ops = this.myTemplate.opsForValue();
if (!this.myTemplate.hasKey(key1)) {
ops.set(key1, user);
}
return key1;
}
앱 실행은 다음과 같이 빈을 주입 : 다음
@SpringBootApplication
public class ApplicationApp extends WebMvcConfigurerAdapter {
// @Autowired
// private RedisTemplate<String,String> template;
@Bean
JedisConnectionFactory jedisConnectionFactory() {
return new JedisConnectionFactory();
}
@Bean
RedisTemplate<String, User> redisTemplate() {
final RedisTemplate<String, User> template = new RedisTemplate<String, User>();
template.setConnectionFactory(jedisConnectionFactory());
template.setKeySerializer(new StringRedisSerializer());
template.setHashValueSerializer(new GenericToStringSerializer<User>(User.class));
template.setValueSerializer(new GenericToStringSerializer<User>(User.class));
return template;
}
@Override
public void addInterceptors(InterceptorRegistry registry) {
// super.addInterceptors(registry);
registry.addInterceptor(new AuthorAccess()).addPathPatterns("/api/sc/**");
}
public static void main(String[] args) throws Exception {
SpringApplication.run(ApplicationApp.class, args);
}
}
, 전화 로그인 서비스가 다음과 같은 오류를 발견했습니다 :
org.springfram ework.core.convert.ConverterNotFoundException : 유형 com.qycloud.oatos.license.domain.User에서 유형을 java.lang.String으로 변환 할 수있는 변환기가 없습니다.
시도해보십시오. template.convertAndSend –